+</pre>
+
+That's it. Well, there may be a wrinkle here.
+
+I don't know whether the definition of a monoid requires the operation to be defined for every pair in its set. In the present case, <code>γ <=< φ</code> isn't fully defined on `T`, but only when <code>φ</code> is a transformation to some `MF'` and <code>γ</code> is a transformation from `F'`. But wherever `<=<` is defined, the monoid laws are satisfied:
+
+<pre>
+ (i) γ <=< φ is also in T
+
+ (ii) (ρ <=< γ) <=< φ = ρ <=< (γ <=< φ)
+
+ (iii.1) unit <=< φ = φ (here φ has to be a natural transformation to M(1C))
+
+ (iii.2) φ = φ <=< unit (here φ has to be a natural transformation from 1C)
+</pre>
+
+If <code>φ</code> is a natural transformation from `F` to `M(1C)` and <code>γ</code> is <code>(φ G')</code>, that is, a natural transformation from `FG` to `MG`, then we can extend (iii.1) as follows:
+
+<pre>
+ γ = (φ G')
+ = ((unit <=< φ) G')
+ = ((join -v- (M unit) -v- φ) G')
+ = (join G') -v- ((M unit) G') -v- (φ G')
+ = (join G') -v- (M (unit G')) -v- γ
+ ??
+ = (unit G') <=< γ
+</pre>
+
+where as we said <code>γ</code> is a natural transformation from some `FG'` to `MG'`.