; pairs
let make_pair = \x y f. f x y in
- let get_1st = \x y. x in ; aka true
- let get_2nd = \x y. y in ; aka false
+ let get_fst = \x y. x in ; aka true
+ let get_snd = \x y. y in ; aka false
; triples
let make_triple = \x y z f. f x y z in
let isempty = \lst. lst (\h sofar. false) true in
let head = \lst. lst (\h sofar. h) junk in
let tail_empty = empty in
- let tail = \lst. (\shift. lst shift (make_pair empty tail_empty) get_2nd)
+ let tail = \lst. (\shift. lst shift (make_pair empty tail_empty) get_snd)
; where shift is
(\h p. p (\t y. make_pair (make_list h t) t)) in
let length = \lst. lst (\h sofar. succ sofar) 0 in
; more efficient reverse builds a left-fold instead
; (make_left_list a (make_left_list b (make_left_list c empty)) ~~> \f z. f c (f b (f a z))
let reverse = (\make_left_list lst. lst make_left_list empty) (\h t f z. t f (f h z)) in
- ; zip [a;b;c] [x; y; z] ~~> [(a,x);(b,y);(c,z)]
+ ; zip [a;b;c] [x;y;z] ~~> [(a,x);(b,y);(c,z)]
let zip = \left right. (\base build. reverse left build base (\x y. reverse x))
; where base is
(make_pair empty (map (\h u. u h) right))
let empty = make_pair true junk in
let make_list = \h t. make_pair false (make_pair h t) in
- let isempty = \lst. lst get_1st in
- let head = \lst. isempty lst err (lst get_2nd get_1st) in
+ let isempty = \lst. lst get_fst in
+ let head = \lst. isempty lst err (lst get_snd get_fst) in
let tail_empty = empty in
- let tail = \lst. isempty lst tail_empty (lst get_2nd get_2nd) in
+ let tail = \lst. isempty lst tail_empty (lst get_snd get_snd) in
; more math with Church numerals
; three strategies for predecessor
let pred_zero = zero in
- let pred = (\shift n. n shift (make_pair zero pred_zero) get_2nd)
+ let pred = (\shift n. n shift (make_pair zero pred_zero) get_snd)
; where shift is
(\p. p (\x y. make_pair (succ x) x)) in ; or
; from Oleg; observe that for any Church numeral n: n I ~~> I
; more efficient comparisons, Oleg's gt provided some simplifications
- let leq = (\base build consume. \m n. n consume (m build base) get_1st)
+ let leq = (\base build consume. \m n. n consume (m build base) get_fst)
; where base is
(make_pair true junk)
; and build is
(\p. make_pair false p)
; and consume is
- (\p. p get_1st p (p get_2nd)) in
+ (\p. p get_fst p (p get_snd)) in
let lt = \m n. not (leq n m) in
- let eq = (\base build consume. \m n. n consume (m build base) get_1st)
+ let eq = (\base build consume. \m n. n consume (m build base) get_fst)
; 2nd element of a pair will now be of the form (K sthg) or I
; we supply the pair being consumed itself as an argument
; getting back either sthg or the pair we just consumed
; and build is
(\p. make_pair false (K p))
; and consume is
- (\p. p get_2nd p) in
+ (\p. p get_snd p) in
; -n is a fixedpoint of \x. add (add n x) x
(make_triple (succ cur) false (succ sofar)) ; continue
)) in
; or
- let sub = (\base build consume. \m n. n consume (m build base) get_1st)
+ let sub = (\base build consume. \m n. n consume (m build base) get_fst)
; where base is
(make_pair zero I) ; see second defn of eq for explanation of 2nd element
; and build is
(\p. p (\x y. make_pair (succ x) (K p)))
; and consume is
- (\p. p get_2nd p) in
+ (\p. p get_snd p) in
let min = \m n. sub m (sub m n) in
; and mtail is
(\dhead d. d (\dz mz df mf drest sel. drest dhead (sel (df dz) (mf mz))))
in
- let div = \n d. divmod n d get_1st in
- let mod = \n d. divmod n d get_2nd in
+ let div = \n d. divmod n d get_fst in
+ let mod = \n d. divmod n d get_snd in
; sqrt n is a fixedpoint of \x. div (div (add n (mul x x)) 2) x
<!--
; my original efficient comparisons
- let leq = (\base build consume. \m n. n consume (m build base) get_1st (\x. false) true)
+ let leq = (\base build consume. \m n. n consume (m build base) get_fst (\x. false) true)
; where base is
(make_pair zero I) ; supplying this pair as an arg to its 2nd term returns the pair
; and build is
(\p. p (\x y. make_pair (succ x) (K p))) ; supplying the made pair as an arg to its 2nd term returns p (the previous pair)
; and consume is
- (\p. p get_2nd p) in
+ (\p. p get_snd p) in
let lt = \m n. not (leq n m) in
let eq = (\base build consume. \m n. n consume (m build base) true (\x. false) true)
; where base is
; and build is
(\p. p (\x y. make_pair (succ x) (K p)))
; and consume is
- (\p. p get_2nd p) in ; or
+ (\p. p get_snd p) in ; or
-->
<!--
-->
+
+<!--
+let list_equal =
+ \left right. left
+ ; here's our f
+ (\hd sofar.
+ ; deconstruct our sofar-pair
+ sofar (\might_be_equal right_tail.
+ ; our new sofar
+ make_pair
+ (and (and might_be_equal (not (isempty right_tail))) (eq? hd (head right_tail)))
+ (tail right_tail)
+ ))
+ ; here's our z
+ ; we pass along the fold a pair
+ ; (might_for_all_i_know_still_be_equal?, tail_of_reversed_right)
+ ; when left is empty, the lists are equal if right is empty
+ (make_pair
+ (not (isempty right))
+ (reverse right)
+ )
+ ; when fold is finished, check sofar-pair
+ (\might_be_equal right_tail. and might_be_equal (isempty right_tail))
+-->
+