-- Or this:
let sysf_true = (\y n -> y) :: Sysf_bool a
- Note that in both OCaml and the Haskell code, the generalization `∀'a` on the free type variable `'a` is implicit. If you really want to, you can supply it explicitly in Haskell by saying:
+ Note that in both OCaml and Haskell code, the generalization `∀α` on the free type variable `α` is implicit. If you really want to, you can supply it explicitly in Haskell by saying:
:set -XExplicitForAll
let { sysf_true :: forall a. Sysf_bool a; ... }
# k 1 true ;;
- : int = 1
- If you can't understand how one term can have several types, recall our discussion in this week's notes of "principal types". (WHERE?)
+ If you can't understand how one term can have several types, recall our discussion in this week's notes of "principal types".