From d541a6500e8d82e1a8862924dca00c360d482c6a Mon Sep 17 00:00:00 2001
From: barker
Date: Mon, 13 Sep 2010 09:37:06 -0400
Subject: [PATCH]
---
assignment1.mdwn | 34 ++++++++++++++++------------------
1 file changed, 16 insertions(+), 18 deletions(-)
diff --git a/assignment1.mdwn b/assignment1.mdwn
index 313db956..9be95780 100644
--- a/assignment1.mdwn
+++ b/assignment1.mdwn
@@ -74,28 +74,32 @@ Here are some defintions in Racket:
(define get-second (lamda (fst) (lambda (snd) snd)))
Now we can write:
+
(define p ((make-pair 10) 20))
(p get-first) ; will evaluate to 10
(p get-second) ; will evaluate to 20
-If you're bothered by having the pair to the left and the function that operates on it come seco\
-nd, think about why it's being done this way: the pair is a package that takes a function for op\
-erating on its elements as an argument, and returns the result of operating on its elemens with \
-that function. In other words, the pair is also a function.
+If you're bothered by having the pair to the left and the function that operates on it come second, think about why it's being done this way: the pair is a package that takes a function for operating on its elements as an argument, and returns the result of operating on its elemens with that function. In other words, the pair is also a function.
If you like, you can disguise what's going on like this:
+
(define lifted-get-first (lambda (p) (p get-first)))
(define lifted-get-second (lambda (p) (p get-second)))
Now you can write:
+
(lifted-get-first p)
+
instead of:
+
(p get-first)
+
However, the latter is still what's going on under the hood.
13. Define a "swap" function that reverses the elements of a pair.
Expected behavior:
+
(define p ((make-pair 10) 20))
((p swap) get-first) ; evaluates to 20
((p swap) get-second) ; evaluates to 10
@@ -106,30 +110,24 @@ Write out the definition of swap in Racket.
14. Define a "dup" function that duplicates its argument to form a pair
whose elements are the same.
Expected behavior:
+
((dup 10) get-first) ; evaluates to 10
((dup 10) get-second) ; evaluates to 10
+
15. Define a "sixteen" function that makes
sixteen copies of its argument (and stores them in a data structure of
your choice).
-16. Inspired by our definition of ordered pairs, propose a data structure capable of representin\
-g ordered tripes. That is,
- (((make-triple M) N) P)
-should return an object that behaves in a reasonable way to serve as a triple. In addition to de\
-fining the make-triple function, you have to show how to extraxt elements of your triple. Write \
-a get-first-of-triple function, that does for triples what get-first does for pairs. Also write \
-get-second-of-triple and get-third-of-triple functions.
+16. Inspired by our definition of ordered pairs, propose a data structure capable of representing ordered tripes. That is,
-> I expect some to come back with the lovely
-> (\f. f first second third)
-> and others, schooled in a certain mathematical perversion, to come back
-> with:
-> (\f. f first (\g. g second third))
+ (((make-triple M) N) P)
+should return an object that behaves in a reasonable way to serve as a triple. In addition to defining the make-triple function, you have to show how to extraxt elements of your triple. Write a get-first-of-triple function, that does for triples what get-first does for pairs. Also write get-second-of-triple and get-third-of-triple functions.
-17. Write a function second-plus-third that when given to your triple, returns the result of add\
-ing the second and third members of the triple.
+17. Write a function second-plus-third that when given to your triple, returns the result of adding the second and third members of the triple.
You can help yourself to the following definition:
+
(define add (lambda (x) (lambda (y) (+ x y))))
+18. [Super hard, unless you have lots of experience programming] Write a function that reverses the order of the elements in a list.
--
2.11.0