From 4288468c7b4a4d0bb6ec7eab2c1d71803716c726 Mon Sep 17 00:00:00 2001
From: Jim Pryor <profjim@jimpryor.net>
Date: Tue, 14 Sep 2010 11:52:17 -0400
Subject: [PATCH] more3 assignment1 tweaks

Signed-off-by: Jim Pryor <profjim@jimpryor.net>
---
 assignment1.mdwn | 41 ++++++++++++++++++++---------------------
 1 file changed, 20 insertions(+), 21 deletions(-)

diff --git a/assignment1.mdwn b/assignment1.mdwn
index 7568717d..05787ca2 100644
--- a/assignment1.mdwn
+++ b/assignment1.mdwn
@@ -42,14 +42,13 @@ evaluates to 10.
 
 <LI>Define an `xor` operator. 
 
-(If you haven't seen this term before, here's a truth table:
+If you haven't seen this term before, here's a truth table:
 
     true xor true = false
     true xor false = true
     false xor true = true
     false xor false = false
 
-)
 
 <LI>Inspired by our definition of boolean values, propose a data structure
 capable of representing one of the two values `black` or `white`. 
@@ -57,7 +56,7 @@ If we have
 one of those values, call it a "black-or-white value", we should be able to
 write:
 
-      	the-value if-black if-white
+	the-value if-black if-white
 
 (where `if-black` and `if-white` are anything), and get back one of `if-black` or
 `if-white`, depending on which of the black-or-white values we started with. Give
@@ -80,19 +79,19 @@ Recall our definitions of ordered pairs.
 
 To extract the first element of a pair p, you write:
 
-        p (\fst \snd. fst)
+	p (\fst \snd. fst)
 
 Here are some definitions in Racket:
 
-        (define make-pair (lambda (fst) (lambda (snd) (lambda (f) ((f fst) snd)))))
-        (define get-first (lambda (fst) (lambda (snd) fst)))
-        (define get-second (lambda (fst) (lambda (snd) snd)))
+	(define make-pair (lambda (fst) (lambda (snd) (lambda (f) ((f fst) snd)))))
+	(define get-first (lambda (fst) (lambda (snd) fst)))
+	(define get-second (lambda (fst) (lambda (snd) snd)))
 
 Now we can write:
 
-        (define p ((make-pair 10) 20))
-        (p get-first)   ; will evaluate to 10
-        (p get-second)  ; will evaluate to 20
+	(define p ((make-pair 10) 20))
+	(p get-first)   ; will evaluate to 10
+	(p get-second)  ; will evaluate to 20
 
 If you're bothered by having the pair to the left and the function that
 operates on it come second, think about why it's being done this way: the pair
@@ -104,16 +103,16 @@ arguments, abstracts, redexes, values---everything.)
 
 If you like, you can disguise what's going on like this:
 
-        (define lifted-get-first (lambda (p) (p get-first)))
-        (define lifted-get-second (lambda (p) (p get-second)))
+	(define lifted-get-first (lambda (p) (p get-first)))
+	(define lifted-get-second (lambda (p) (p get-second)))
 
 Now you can write:
 
-        (lifted-get-first p)
+	(lifted-get-first p)
 
 instead of:
 
-        (p get-first)
+	(p get-first)
 
 However, the latter is still what's going on under the hood.
 
@@ -123,9 +122,9 @@ However, the latter is still what's going on under the hood.
 
 Expected behavior:
 
-        (define p ((make-pair 10) 20))
-        ((p swap) get-first) ; evaluates to 20
-        ((p swap) get-second) ; evaluates to 10
+	(define p ((make-pair 10) 20))
+	((p swap) get-first) ; evaluates to 20
+	((p swap) get-second) ; evaluates to 10
 
 Write out the definition of swap in Racket.
 
@@ -134,8 +133,8 @@ Write out the definition of swap in Racket.
 whose elements are the same.
 Expected behavior:
 
-        ((dup 10) get-first) ; evaluates to 10
-        ((dup 10) get-second) ; evaluates to 10
+	((dup 10) get-first) ; evaluates to 10
+	((dup 10) get-second) ; evaluates to 10
 
 <LI>Define a `sixteen` function that makes
 sixteen copies of its argument (and stores them in a data structure of
@@ -143,7 +142,7 @@ your choice).
 
 <LI>Inspired by our definition of ordered pairs, propose a data structure capable of representing ordered triples. That is,
 
-        (((make-triple M) N) P)
+	(((make-triple M) N) P)
 
 should return an object that behaves in a reasonable way to serve as a triple. In addition to defining the `make-triple` function, you have to show how to extract elements of your triple. Write a `get-first-of-triple` function, that does for triples what `get-first` does for pairs. Also write `get-second-of-triple` and `get-third-of-triple` functions.
 
@@ -151,7 +150,7 @@ should return an object that behaves in a reasonable way to serve as a triple. I
 
 You can help yourself to the following definition:
 
-    (define add (lambda (x) (lambda (y) (+ x y))))
+	(define add (lambda (x) (lambda (y) (+ x y))))
 
 <!-- Write a function that reverses the order of the elements in a list. [Only attempt this problem if you're feeling frisky, it's super hard unless you have lots of experience programming.]  -->
 
-- 
2.11.0