X-Git-Url: http://lambda.jimpryor.net/git/gitweb.cgi?p=lambda.git;a=blobdiff_plain;f=assignment3.mdwn;h=f93afd6110ce1e32550d37639f6f7ac7f3a77bc4;hp=e240b732b1405e176d696bbab3c5974a1d125f35;hb=b059b718b62f3b4beffb3bd7fbe66af01069f9c9;hpb=e17c03bd8ce5b051ce06e123d3ce65d6086591be diff --git a/assignment3.mdwn b/assignment3.mdwn index e240b732..f93afd61 100644 --- a/assignment3.mdwn +++ b/assignment3.mdwn @@ -1,151 +1,97 @@ Assignment 3 ------------ -Erratum corrected 11PM Sun 3 Oct: the following line - - let tb = (make_list t12 (make_list t3 empty)) in - -originally read - - let tb = (make_list t12 t3) in - -This has been corrected below, and in the preloaded evaluator for -working on assignment 3, available here: [[assignment 3 evaluator]]. - -
- Once again, the lambda evaluator will make working through this assignment much faster and more secure. -#Writing recursive functions on version 1 style lists# - -Recall that version 1 style lists are constructed like this (see -[[lists and numbers]]): - - ; booleans - let true = \x y. x in - let false = \x y. y in - let and = \l r. l (r true false) false in - - let make_pair = \f s g. g f s in - let get_fst = true in - let get_snd = false in - let empty = make_pair true junk in - let isempty = \x. x get_fst in - let make_list = \h t. make_pair false (make_pair h t) in - let head = \l. isempty l err (l get_snd get_fst) in - let tail = \l. isempty l err (l get_snd get_snd) in - - ; a list of numbers to experiment on - let mylist = make_list 1 (make_list 2 (make_list 3 empty)) in - - ; church numerals - let iszero = \n. n (\x. false) true in - let succ = \n s z. s (n s z) in - let add = \l r. l succ r in - let mul = \m n s. m (n s) in - let pred = (\shift n. n shift (make\_pair 0 0) get\_snd) (\p. p (\x y. make\_pair (succ x) x)) in - let leq = \m n. iszero(n pred m) in - let eq = \m n. and (leq m n)(leq n m) in - - ; a fixed-point combinator for defining recursive functions - let Y = \f. (\h. f (h h)) (\h. f (h h)) in - let length = Y (\length l. isempty l 0 (succ (length (tail l)))) in - let fold = Y (\f l g z. isempty l z (g (head l)(f (tail l) g z))) in - - eq 2 2 yes no +##Writing recursive functions on version 1 style lists## + +Recall that version 1 style lists are constructed like this: + +
+; booleans
+let true = \x y. x in
+let false = \x y. y in
+let and = \l r. l (r true false) false in
+
+; version 1 lists
+let makePair = \f s g. g f s in
+let fst = true in
+let snd = false in
+let nil = makePair true meh in
+let isNil = \x. x fst in
+let makeList = \h t. makePair false (makePair h t) in
+let head = \l. isNil l err (l snd fst) in
+let tail = \l. isNil l err (l snd snd) in
+
+; a list of numbers to experiment on
+let mylist = makeList 1 (makeList 2 (makeList 3 nil)) in
+
+; a fixed-point combinator for defining recursive functions 
+let Y = \f. (\h. f (h h)) (\h. f (h h)) in
+
+; church numerals
+let isZero = \n. n (\x. false) true in
+let succ = \n s z. s (n s z) in
+let mult = \m n s. m (n s) in
+let length = Y (\length l. isNil l 0 (succ (length (tail l)))) in
+let predecessor = \n. length (tail (n (\p. makeList meh p) nil)) in
+let leq = ; (leq m n) will be true iff m is less than or equal to n
+  Y (\leq m n. isZero m true (isZero n false (leq (predecessor m)(predecessor n)))) in
+let eq = \m n. and (leq m n)(leq n m) in
+
+eq 3 3
+
Then `length mylist` evaluates to 3. -1. What does `head (tail (tail mylist))` evaluate to? +1. Warm-up: What does `head (tail (tail mylist))` evaluate to? 2. Using the `length` function as a model, and using the predecessor function, write a function that computes factorials. (Recall that n!, the factorial of n, is n times the factorial of n-1.) - Warning: it takes a long time for my browser to compute factorials larger than 4! +Warning: my browser isn't able to compute factorials of numbers +greater than 2 (it does't provide enough resources for the JavaScript +interpreter; web pages are not supposed to be that computationally +intensive). -3. (Easy) Write a function `equal_length` that returns true just in case -two lists have the same length. That is, - equal_length mylist (make_list junk (make_list junk (make_list junk empty))) ~~> true +3. Write a function `listLenEq` that returns true just in case two lists have the +same length. That is, - equal_length mylist (make_list junk (make_list junk empty))) ~~> false + listLenEq mylist (makeList meh (makeList meh (makeList meh nil))) ~~> true + listLenEq mylist (makeList meh (makeList meh nil))) ~~> false -4. (Still easy) Now write the same function, but don't use the length -function. +4. Now write the same function, but don't use the length function (hint: use `leq` as a model). -5. In assignment 2, we discovered that version 3-type lists (the ones -that -work like Church numerals) made it much easier to define operations -like `map` and `filter`. But now that we have recursion in our -toolbox, -reasonable map and filter functions for version 1 lists are within our -reach. Give definitions for `map` and a `filter` for verson 1 type -lists. +##Trees## -#Computing with trees# +Since we'll be working with linguistic objects, let's approximate +trees as follows: a tree is a version 1 list +a Church number is a tree, and +if A and B are trees, then (make-pair A B) is a tree. -Linguists analyze natural language expressions into trees. -We'll need trees in future weeks, and tree structures provide good -opportunities for learning how to write recursive functions. -Making use of the resources we have at the moment, we can approximate -trees as follows: instead of words, we'll use Church numerals. -Then a tree will be a (version 1 type) list in which each element is -itself a tree. For simplicity, we'll adopt the convention that -a tree of length 1 must contain a number as its only element. -Then we have the following representations: -
-   (a)           (b)             (c)
-    .
-   /|\            /\              /\
-  / | \          /\ 3            1 /\
-  1 2  3        1  2               2 3
+[The following should be correct, but won't run in my browser:
 
-[[1];[2];[3]]  [[[1];[2]];[3]]   [[1];[[2];[3]]]
-
- -Limitations of this scheme include the following: there is no easy way -to label a constituent with a syntactic category (S or NP or VP, -etc.), and there is no way to represent a tree in which a mother has a -single daughter. - -When processing a tree, you can test for whether the tree contains -only a numeral (in which case the tree is leaf node) by testing for -whether the length of the list is less than or equal to 1. This will -be your base case for your recursive functions that operate on these -trees. - -
    -
  1. Write a function that sums the values at the leaves in a tree. - -Expected behavior: +let factorial = Y (\fac n. isZero n 1 (mult n (fac (predecessor n)))) in - let t1 = (make_list 1 empty) in - let t2 = (make_list 2 empty) in - let t3 = (make_list 3 empty) in - let t12 = (make_list t1 (make_list t2 empty)) in - let t23 = (make_list t2 (make_list t3 empty)) in - let ta = (make_list t1 t23) in - let tb = (make_list t12 (make_list t3 empty)) in - let tc = (make_list t1 (make_list t23 empty)) in - - sum-leaves t1 ~~> 1 - sum-leaves t2 ~~> 2 - sum-leaves t3 ~~> 3 - sum-leaves t12 ~~> 3 - sum-leaves t23 ~~> 5 - sum-leaves ta ~~> 6 - sum-leaves tb ~~> 6 - sum-leaves tc ~~> 6 - - -
  2. Write a function that counts the number of leaves. +
    +let reverse = 
    +  Y (\rev l. isNil l nil 
    +                   (isNil (tail l) l 
    +                          (makeList (head (rev (tail l))) 
    +                                    (rev (makeList (head l) 
    +                                                   (rev (tail (rev (tail l))))))))) in
    +
    +reverse (makeList 1 (makeList 2 (makeList 3 nil)))
    +
    -
+It may require more resources than my browser is willing to devote to +JavaScript.]