The seminar is now going to begin talking about more **imperatival** or **effect**-like elements in programming languages. The only effect-like element we've encountered so far is the possibility of divergence, in languages that permit fixed point combinators and so have the full power of recursion. What it means for something to be effect-like, and why this counts as an example of such, will emerge.
-Other effect-like elements in a language include: printing (recall the [[damn]] example at the start of term); continuations (also foreshadowed in the [[damn]] example) and exceptions (foreshadowed in our discussion of abortable list traversals in [[week4]]); and **mutation**. This last notion is our topic this week.
+Other effect-like elements in a language include: printing; continuations (which we'll study more in the coming weeks) and exceptions (like OCaml's `failwith "message"` or `raise Not_found`); and **mutation**. This last notion is our topic this week.
## Mutation##
-What is mutation? It's helpful to build up to this in a series of fragments. For pedagogical purposes, we'll be using a made-up language that's syntactically similar to, but not quite the same as, OCaml.
+What is mutation? It's helpful to build up to this in a series of fragments. For present pedagogical purposes, we'll be using a made-up language that's syntactically similar to, but not quite the same as, OCaml. (It's not quite Kapulet either.)
Recall from earlier discussions that the following two forms are equivalent:
- [A] let x be EXPRESSION in
- BODY
+ [A] let x = EXPRESSION in
+ BODY
- (lambda (x) -> BODY) (EXPRESSION)
+ (\x. BODY) (EXPRESSION)
This should seem entirely familiar:
- [B] let x be 1 + 2 in
- let y be 10 in
- (x + y, x + 20)
- ; evaluates to (13, 23)
+ [B] let y = 1 + 2 in
+ let x = 10 in
+ (x + y, 20 + y)
+ ; evaluates to (13, 23)
-In fragment [B], we bound the variables `x` and `y` to `int`s. We can also bind variables to function values, as here:
+In our next fragment, we re-use a variable that had been bound to another value in a wider context:
+
+ [C] let y = 2 in ; will be shadowed by the binding on the next line
+ let y = 3 in
+ (10 + y, 20 + y)
+ ; evaluates to (13, 23)
+
+As you can see, the narrowest assignment is what's effective. This is just like in predicate logic: consider <code>∃y (Fy and ∃y ~Fy)</code>. The computer-science terminology to describe this is that the narrower assignment of `y` to the value 3 **shadows** the wider assignment to 2.
+
+I call attention to this because you might casually describe it as "changing the value that y is assigned to." But what we'll see below is a more exotic phenomenon that merits that description better.
- [C] let f be (lambda (x, y) -> x + y + 1) in
- (f (10, 2), f (20, 2))
- ; evaluates to (13, 23)
+In the previous fragments, we bound the variables `x` and `y` to `int`s. We can also bind variables to function values, as here:
+
+ [D] let f = (\x y. x + y + 1) in
+ (f 10 2, f 20 2)
+ ; evaluates to (13, 23)
If the expression that evaluates to a function value has a free variable in it, like `y` in the next fragment, it's interpreted as bound to whatever value `y` has in the surrounding lexical context:
- [D] let y be 3 in
- let f be (lambda (x) -> x + y) in
- (f (10), f (20))
- ; evaluates to (13, 23)
+ [E] let y = 3 in
+ let f = (\x. x + y) in
+ let y = 2 in
+ (f 10, y, f 20)
+ ; evaluates to (13, 2, 23)
Other choices about how to interpret free variables are also possible (you can read about "lexical scope" versus "dynamic scope"), but what we do here is the norm in functional programming languages, and seems to be easiest for programmers to reason about.
-In our next fragment, we re-use a variable that had been bound to another value in a wider context:
+Sometimes bindings are shadowed merely in a temporary, local context, as here:
- [E] let y be 2 in
- let y be 3 in
- (y + 10, y + 20)
- ; evaluates to (13, 23)
+ [F] let y = 3 in
+ let f = (\x. let y = 2 in
+ ; here the most local assignment to y applies
+ x + y) in
+ ; here the binding of y to 2 has expired
+ (y, f 10, y, f 20)
+ ; evaluates to (3, 12, 3, 22)
-As you can see, the narrowest assignment is what's effective. This is just like in predicate logic: consider <code>∃y (Fy and ∃y ~Fy)</code>. The computer-science terminology to describe this is that the narrower assignment of `y` to the value 3 **shadows** the wider assignment to 2.
+Notice that the `y`s in the tuple at the end use the outermost binding of `y` to `3`, but the `y` in `x + y` in the body of the `f` function uses the more local binding.
+
+OK, now we're ready for our main event, **mutable variables.** We'll introduce new syntax to express an operation where we're not shadowing a wider assignment, but *changing* the original assignment. The new syntax will show up both when we introduce the variable, using `var y = ...` rather than `let y = ...`; and also when we change `y`'s value using `set`.
+
+ [G] var y = 3 in
+ let f = (\x. set y to 2 then
+ x + y) in
+ ; here the change in what value y was assigned *sticks*
+ ; because we *updated* the value of the original variable y
+ ; instead of introducing a new y with a narrower scope
+ (y, f 10, y, f 20)
+ ; evaluates to (3, 12, 2, 22)
-I call attention to this because you might casually describe it as "changing the value that y is assigned to." What we'll go on to see is a more exotic phenomenon that merits that description better.
-
-Sometimes the shadowing is merely temporary, as here:
-
- [F] let y be 2 in
- let f be (lambda (x) ->
- let y be 3 in
- ; here the most local assignment to y applies
- x + y
- ) in
- ; here the assignment of 3 to y has expired
- (f (10), y, f (20))
- ; evaluates to (13, 2, 23)
-
-OK, now we're ready for our main event, **mutable variables.** We'll introduce new syntax to express an operation where we're not shadowing a wider assignment, but *changing* the original assignment:
-
- [G] let y be 2 in
- let f be (lambda (x) ->
- change y to 3 then
- x + y
- ) in
- ; here the change in what value y was assigned *sticks*
- ; because we *updated* the value of the original variable y
- ; instead of introducing a new y with a narrower scope
- (f (10), y, f (19))
- ; evaluates to (13, 3, 23)
-
-In languages that have native syntax for this, there are two styles in which it can be expressed. The *implicit style* is exemplified in fragment [G] above, and also in languages like C:
-
- {
- int y = 2; // this is like "let y be 2 in ..."
- ...
- y = 3; // this is like "change y to 3 then ..."
- return x + y; // this is like "x + y"
- }
+Notice the difference in the how the second `y` is evaluated in the tuple at the end. By the way, I am assuming here that the tuple gets evaluated left-to-right. Other languages may or may not conform to that. OCaml doesn't always.
+
+In languages that have native syntax for mutation, there are two styles in which it can be expressed. The *implicit style* is exemplified in fragment [G] above, and also in languages like C:
+
+ {
+ int y = 3; // this is like "var y = 3 in ..."
+ ...
+ y = 2; // this is like "set y to 2 then ..."
+ return x + y; // this is like "x + y"
+ }
A different possibility is the *explicit style* for handling mutation. Here we explicitly create and refer to new "reference cells" to hold our values. When we change a variable's value, the variable stays associated with the same reference cell, but that reference cell's contents get modified. The same thing happens in the semantic machinery underlying implicit-style mutable variables, but there it's implicit---the reference cells aren't themselves expressed by any term in the object language. In explicit-style mutation, they are. OCaml has explicit-style mutation. It looks like this:
- let ycell = ref 2 (* this creates a new reference cell *)
- ...
- in let () = ycell := 3 (* this changes the contents of that cell to 3 *)
- (* the return value of doing so is () *)
- (* other return values could also be reasonable: *)
- (* such as the old value of ycell, the new value, an arbitrary int, and so on *)
- in x + !ycell;; (* the !ycell operation "dereferences" the cell---it retrieves the value it contains *)
+ let ycell = ref 3 (* this creates a new reference cell *)
+ ... in
+ let () = ycell := 2 in (* this changes the contents of that cell to 2 *)
+ (* the return value of doing so is () *)
+ (* other return values could also be reasonable: *)
+ (* such as the old value of ycell, the new value, an arbitrary int, and so on *)
+ x + !ycell;; (* the !ycell operation "dereferences" the cell---it retrieves the value it contains *)
Scheme is similar. There are various sorts of reference cells available in Scheme. The one most like OCaml's `ref` is a `box`. Here's how we'd write the same fragment in Scheme:
- (let ([ycell (box 2)])
- ...
- (set-box! ycell 3)
- (+ x (unbox ycell)))
+ (let ([ycell (box 3)])
+ ...
+ (set-box! ycell 2)
+ (+ x (unbox ycell)))
C has explicit-style mutable variables, too, which it calls *pointers*. But simple variables in C are already mutable, in the implicit style. Scheme also has both styles of mutation. In addition to the explicit boxes, Scheme also lets you mutate unboxed variables:
- (begin
- (define x 1)
- (set! x 2)
- x)
- ; evaluates to 2
+ (begin
+ (define y 3)
+ (set! y 2)
+ y)
+ ; evaluates to 2
When dealing with explicit-style mutation, there's a difference between the types and values of `ycell` and `!ycell` (or in Scheme, `(unbox ycell)`). The former has the type `int ref`: the variable `ycell` is assigned a reference cell that contains an `int`. The latter has the type `int`, and has whatever value is now stored in the relevant reference cell. In an implicit-style framework though, we only have the resources to refer to the contents of the relevant reference cell. `y` in fragment [G] or the C snippet above has the type `int`, and only ever evaluates to `int` values.
OCaml does *not* guarantee what order expressions will be evaluated in arbitrary contexts. For example, in the following fragment, you cannot rely on `expression_a` being evaluated before `expression_b` before `expression_c`:
- let triple = (expression_a, expression_b, expression_c)
+ let triple = (expression_a, expression_b, expression_c)
OCaml does however guarantee that different let-expressions are evaluated in the order they lexically appear. So in the following fragment, `expression_a` *will* be evaluated before `expression_b` and that before `expression_c`:
- let a = expression_a
- in let b = expression_b
- in expression_c
+ let a = expression_a in
+ let b = expression_b in
+ expression_c
Scheme does the same. (*If* you use Scheme's `let*`, but not if you use its `let`. I agree this is annoying.)
If `expression_a` and `expression_b` evaluate to (), for instance if they're something like `ycell := !ycell + 1`, that can also be expressed in OCaml as:
- let () = expression_a
- in let () = expression_b
- in expression_c
+ let () = expression_a in
+ let () = expression_b in
+ expression_c
And OCaml has a syntactic shorthand for this form, namely to use semi-colons:
- expression_a; expression_b; expression_c
+ expression_a; expression_b; expression_c
This is not the same role that semi-colons play in list expressions, like `[1; 2; 3]`. To be parsed correctly, these semi-colon'ed complexes sometimes need to be enclosed in parentheses or a `begin ... end` construction:
- (expression_a; expression_b; expression_c)
+ (expression_a; expression_b; expression_c)
- begin expression_a; expression_b; expression_c end
+ begin expression_a; expression_b; expression_c end
Scheme has a construction similar to the latter:
- (begin (expression_a) (expression_b) (expression_c))
+ (begin (expression_a) (expression_b) (expression_c))
Though often in Scheme, the `(begin ...)` is implicit and doesn't need to be explicitly inserted, as here:
- (lambda (x) (expression_a) (expression_b) (expression_c))
+ (lambda (x) (expression_a) (expression_b) (expression_c))
-Another way to control evaluation order, you'll recall from [[week6]], is to use **thunks**. These are functions that only take the uninformative `()` as an argument, such as this:
+Another way to control evaluation order, you'll recall from previous discussion, is to use **thunks**. These are functions that only take the uninformative `()` as an argument, such as this:
- let f () = ...
+ let f () = ... in
+ ...
or this:
- let f = fun () -> ...
+ let f = fun () -> ... in
+ ...
In Scheme these are written as functions that take 0 arguments:
- (lambda () ...)
+ (let* ([f (lambda () ...)]) ...)
or:
- (define (f) ...)
+ (define (f) ...)
+ ...
How could such functions be useful? Well, as always, the context in which you build a function need not be the same as the one in which you apply it to some arguments. So for example:
- let ycell = ref 1
- in let f () = ycell := !ycell + 1
- in let z = !ycell
- in f ()
- in z;;
-
-We don't apply (or call or execute or however you want to say it) the function `f` until after we've extracted `ycell`'s value and assigned it to `z`. So `z` will get assigned 1. If on the other hand we called `f ()` before evaluating `let z = !ycell`, then `z` would have gotten assigned a different value.
-
-In languages with mutable variables, the free variables in a function definition are usually taken to refer back to the same *reference cells* they had in their lexical contexts, and not just their original value. So if we do this for instance:
-
- let factory (starting_value : int) =
- let free_var = ref starting_value
- in let getter () =
- !free_var
- in let setter (new_value : int) =
- free_var := new_value
- in (getter, setter)
- in let (getter, setter) = factory 1
- in let first = getter ()
- in let () = setter 2
- in let second = getter ()
- in let () = setter 3
- in let third = getter ()
- in (first, second, third)
-
+ let ycell = ref 1 in
+ let incr_y () = ycell := !ycell + 1 in
+ let y = !ycell in
+ incr_y () in
+ y
+
+We don't apply (or call or execute or however you want to say it) the function `incr_y` until after we've extracted `ycell`'s value and assigned it to `y`. So `y` will get assigned `1`. If on the other hand we called `incr_y ()` before evaluating `let y = !ycell`, then `y` would have gotten assigned a different value.
+
+In languages with mutable variables, the free variables in a function definition are often taken to refer back to the same *reference cells* they had in their lexical contexts, and not just their original value. So if we do this for instance:
+
+ let factory (starting_value : int) =
+ let free_var = ref starting_value in
+ let getter () = !free_var in
+ let setter (new_value : int) = free_var := new_value in
+ (getter, setter) in
+ let (getter, setter) = factory 1 in
+ let first = getter () in
+ let () = setter 2 in
+ let second = getter () in
+ let () = setter 3 in
+ let third = getter () in
+ (first, second, third)
+
At the end, we'll get `(1, 2, 3)`. The reference cell that gets updated when we call `setter` is the same one that gets fetched from when we call `getter`. This should seem very intuitive here, since we're working with explicit-style mutation. When working with a language with implicit-style mutation, it can be more surprising. For instance, here's the same fragment in Python, which has implicit-style mutation:
- def factory (starting_value):
- free_var = starting_value
- def getter ():
- return free_var
- def setter (new_value):
- # the next line indicates that we're using the
- # free_var from the surrounding function, not
- # introducing a new local variable with the same name
- nonlocal free_var
- free_var = new_value
- return getter, setter
- getter, setter = factory (1)
- first = getter ()
- setter (2)
- second = getter ()
- setter (3)
- third = getter ()
- (first, second, third)
+ def factory (starting_value):
+ free_var = starting_value
+ def getter ():
+ return free_var
+ def setter (new_value):
+ # the next line indicates that we're using the
+ # free_var from the surrounding function, not
+ # introducing a new local variable with the same name
+ nonlocal free_var
+ free_var = new_value
+ return getter, setter
+ getter, setter = factory (1)
+ first = getter ()
+ setter (2)
+ second = getter ()
+ setter (3)
+ third = getter ()
+ (first, second, third)
Here, too, just as in the OCaml fragment, all the calls to getter and setter are working with a single mutable variable `free_var`.
If however you called `factory` twice, you'd have different `getter`/`setter` pairs, each of which had their own, independent `free_var`. In OCaml:
- let factory (starting_val : int) =
- ... (* as above *)
- in let (getter, setter) = factory 1
- in let (getter', setter') = factory 1
- in let () = setter 2
- in getter' ()
+ let factory (starting_val : int) =
+ ... (* as above *) in
+ let (getter, setter) = factory 1 in
+ let (getter', setter') = factory 1 in
+ let () = setter 2 in
+ getter' ()
-Here, the call to `setter` only mutated the reference cell associated with the `getter`/`setter` pair. The reference cell associated with `getter'` hasn't changed, and so `getter' ()` will still evaluate to 1.
+Here, the call to `setter` only mutated the reference cell associated with the `getter`/`setter` pair. The reference cell associated with `getter'` hasn't changed, and so `getter' ()` will still evaluate to `1`.
Notice in these fragments that once we return from inside the call to `factory`, the `free_var` mutable variable is no longer accessible, except through the helper functions `getter` and `setter` that we've provided. This is another way in which a thunk like `getter` can be useful: it still has access to the `free_var` reference cell that was created when it was, because its free variables are interpreted relative to the context in which `getter` was built, even if that context is otherwise no longer accessible. What `getter ()` evaluates to, however, will very much depend on *when* we evaluate it---in particular, it will depend on which calls to the corresponding `setter` were evaluated first.
+
##Referential opacity##
In addition to order-sensitivity, when you're dealing with mutable variables you also give up a property that computer scientists call "referential transparency." It's not obvious whether they mean exactly the same by that as philosophers and linguists do, or only something approximately the same.
The core idea to referential transparency is that when the same value is supplied to a context, the whole should always evaluate the same way. Mutation makes it possible to violate this. Consider:
- let ycell = ref 1
- in let f x = x + !ycell
- in let first = f 1 (* first is assigned the value 2 *)
- in ycell := 2; let second = f 1 (* second is assigned the value 3 *)
- in first = second;; (* not true! *)
+ let ycell = ref 1 in
+ let f x = x + !ycell in
+ let first = f 1 in (* first is assigned the value 2 *)
+ ycell := 2; let second = f 1 in (* second is assigned the value 3 *)
+ first = second;; (* not true! *)
Notice that the two invocations of `f 1` yield different results, even though the same value is being supplied as an argument to the same function.
Similarly, functions like these:
- let f cell = !cell;;
+ let f cell = !cell;;
- let g cell = cell := !cell + 1; !cell;;
+ let g cell = cell := !cell + 1; !cell;;
may return different results each time they're invoked, even if they're always supplied one and the same reference cell as argument.
Computer scientists also associate referential transparency with a kind of substitution principle, illustrated here:
- let x = 1
- in (x, x)
+ let x = 1 in
+ (x, x)
should evaluate the same as:
- let x = 1
- in (x, 1)
+ let x = 1
+ (x, 1)
or:
- (1, 1)
+ (1, 1)
Notice, however, that when mutable variables are present, the same substitution patterns can't always be relied on:
- let ycell = ref 1
- in ycell := 2; !ycell
- (* evaluates to 2 *)
-
- (ref 1) := 2; !(ref 1)
- (* creates a ref 1 cell and changes its contents *)
- (* then creates a *new* ref 1 cell and returns *its* contents *)
+ let ycell = ref 1 in
+ ycell := 2; !ycell
+ (* evaluates to 2 *)
+ (ref 1) := 2; !(ref 1)
+ (* creates a ref 1 cell and changes its contents *)
+ (* then creates a *new* ref 1 cell and returns *its* contents *)
+ (* so evaluates to 1 *)
We'll think about how to implement explicit-style mutation first. We suppose that we add some new syntactic forms to a language, let's call them `newref`, `deref`, and `setref`. And now we want to expand the semantics for the language so as to interpret these new forms.
-Well, part of our semantic machinery will be an assignment function, call it `g`. Somehow we should keep track of the types of the variables and values we're working with, but we won't pay much attention to that now. In fact, we won't even bother much at this point with the assignment function. Below we'll pay more attention to it.
+Well, part of our semantic machinery will be an assignment function or environment, call it `e`. Somehow we should keep track of the *types* of the variables and values we're working with, but we won't pay much attention to that now. In fact, we won't even bother much at this point with the assignment function. Below we'll pay more attention to it.
+
+In addition to the assignment function, we'll also need a way to keep track of how many reference cells have been "allocated" (using `newref`), and what their current values are. We'll suppose all the reference cells are organized in a single data structure we might call a table or **store**. This might be a big heap of memory. For our purposes, we'll suppose that reference cells only ever contain `int`s, and we'll let the store be a list of `int`s.
-In addition to the assignment function, we'll also need a way to keep track of how many reference cells have been "allocated" (using `newref`), and what their current values are. We'll suppose all the reference cells are organized in a single data structure we'll call a **store**. This might be a big heap of memory. For our purposes, we'll suppose that reference cells only ever contain `int`s, and we'll let the store be a list of `int`s.
+We won't suppose that the metalanguage we use to express the semantics of our mutation-language itself has any mutation facilities. Instead, we'll think about how to model mutation in a wholly declarative or functional or *static* metalanguage.
In many languages, including OCaml, the first position in a list is indexed `0`, the second is indexed `1` and so on. If a list has length 2, then there won't be any value at index `2`; that will be the "next free location" in the list.
Before we brought mutation on the scene, our language's semantics will have looked something like this:
-> \[[expression]]<sub>g</sub> = value
+> \[[expression]]<sub>e</sub> = result
-Now we're going to relativize our interpretations not only to the assignment function `g`, but also to the current store, which I'll label `s`. Additionally, we're going to want to allow that evaluating some functions might *change* the store, perhaps by allocating new reference cells or perhaps by updating the contents of some existing cells. So the interpretation of an expression won't just return a value; it will also return a possibly updated store. We'll suppose that our interpretation function does this quite generally, even though for many expressions in the language, the store that's returned will be the same one that the interpretation function started with:
+Now we're going to relativize our interpretations not only to the environment `e`, but also to the current store, which I'll label `s`. Additionally, we're going to want to allow that evaluating some functions might *change* the store, perhaps by allocating new reference cells or perhaps by modifying the contents of some existing cells. So the interpretation of an expression won't just return a result; it will also return a possibly updated store. We'll suppose that our interpretation function does this quite generally, even though for many expressions in the language, the store that's returned will be the same one that the interpretation function started with:
-> \[[expression]]<sub>g s</sub> = (value, s')
+> \[[expression]]<sub>e s</sub> = (result, s')
For expressions we already know how to interpret, expect `s'` to just be `s`.
An exception is complex expressions like `let var = expr1 in expr2`. Part of
to allow that in doing that, the store may have already been updated. We want
to use that possibly updated store when interpreting `expr2`. Like this:
- let rec eval expression g s =
- match expression with
- ...
- | Let (c, expr1, expr2) ->
- let (value, s') = eval expr1 g s
- (* s' may be different from s *)
- (* now we evaluate expr2 in a new environment where c has been associated
- with the result of evaluating expr1 in the current environment *)
- eval expr2 ((c, value) :: g) s'
- ...
+ let rec eval expression e s = match expression with
+ ...
+ | Let (var, expr1, expr2) ->
+ let (res1, s') = eval expr1 e s
+ (* s' may be different from s *)
+ (* now we evaluate expr2 in a new environment where var has been associated
+ with the result of evaluating expr1 in the current environment *)
+ eval expr2 ((var, res1) :: e) s'
+ ...
Similarly:
- ...
- | Addition (expr1, expr2) ->
- let (value1, s') = eval expr1 g s
- in let (value2, s'') = eval expr2 g s'
- in (value1 + value2, s'')
- ...
+ ...
+ | Apply (Apply(PrimitiveAddition, expr1), expr2) ->
+ let (res1, s') = eval expr1 e s in
+ let (res2, s'') = eval expr2 e s' in
+ (res1 + res2, s'')
+ ...
Let's consider how to interpet our new syntactic forms `newref`, `deref`, and `setref`:
-1. When `expr` evaluates to `starting_val`, **newref expr** should allocate a new reference cell in the store and insert `starting_val` into that cell. It should return some "key" or "index" or "pointer" to the newly created reference cell, so that we can do things like:
+1. When `expr` evaluates to `starting_val`, **newref expr** should allocate a new reference cell in the store and insert `starting_val` into that cell. It should return some "key" or "index" or "pointer" to the newly created reference cell, so that we can do things like:
- let ycell = newref 1
- in ...
+ let ycell = newref 1 in
+ ...
- and be able to refer back to that cell later by using the value that we assigned to the variable `ycell`. In our simple implementation, we're letting the store just be an `int list`, and we can let the "keys" be indexes in that list, which are (also) just `int`s. Somehow we should keep track of which variables are assigned `int`s as `int`s and which are assigned `int`s as indexes into the store. So we'll create a special type to wrap the latter:
+ and be able to refer back to that cell later by using the result that we assigned to the variable `ycell`. In our simple implementation, we're letting the store just be an `int list`, and we can let the "keys" be indexes in that list, which are (also) just `int`s. Somehow we should keep track of which variables are assigned `int`s as `int`s and which are assigned `int`s as indexes into the store. So we'll create a special type to wrap the latter:
- type store_index = Index of int;;
+ type store_index = Index of int;;
- Our interpretation function will look something like this:
-
- let rec eval expression g s =
- match expression with
- ...
- | Newref (expr) ->
- let (starting_val, s') = eval expr g s
- (* note that s' may be different from s, if expr itself contained any mutation operations *)
- (* now we want to retrieve the next free index in s' *)
- in let new_index = List.length s'
- (* now we want to insert starting_val there; the following is an easy but inefficient way to do it *)
- in let s'' = List.append s' [starting_val]
- (* now we return a pair of a wrapped new_index, and the new store *)
- in (Index new_index, s'')
- ...
+ Our interpretation function will look something like this:
+
+ let rec eval expression e s = match expression with
+ ...
+ | Newref (expr) ->
+ let (starting_val, s') = eval expr e s in
+ (* note that s' may be different from s, if expr itself contained any mutation operations *)
+ (* now we want to retrieve the next free index in s' *)
+ let new_index = List.length s' in
+ (* now we want to insert starting_val there; the following is an easy but inefficient way to do it *)
+ let s'' = List.append s' [starting_val] in
+ (* now we return a pair of a wrapped new_index, and the new store *)
+ (Index new_index, s'')
+ ...
-2. When `expr` evaluates to a `store_index`, then **deref expr** should evaluate to whatever value is at that index in the current store. (If `expr` evaluates to a value of another type, `deref expr` is undefined.) In this operation, we don't change the store at all; we're just reading from it. So we'll return the same store back unchanged (assuming it wasn't changed during the evaluation of `expr`).
+2. When `expr` evaluates to a `store_index`, then **deref expr** should evaluate to whatever value is at that index in the current store. (If `expr` evaluates to a value of another type, `deref expr` is undefined.) In this operation, we don't change the store at all; we're just reading from it. So we'll return the same store back unchanged (assuming it wasn't changed during the evaluation of `expr`).
- let rec eval expression g s =
- match expression with
- ...
- | Deref (expr) ->
- let (Index n, s') = eval expr g s
- (* note that s' may be different from s, if expr itself contained any mutation operations *)
- in (List.nth s' n, s')
- ...
+ let rec eval expression e s =
+ match expression with
+ ...
+ | Deref (expr) ->
+ let (Index n, s') = eval expr e s in
+ (* s' may be different from s, if expr itself contained any mutation operations *)
+ (List.nth s' n, s')
+ ...
-3. When `expr1` evaluates to a `store_index` and `expr2` evaluates to an `int`, then **setref expr1 expr2** should have the effect of changing the store so that the reference cell at that index now contains that `int`. We have to make a decision about what value the `setref ...` call should itself evaluate to; OCaml makes this `()` but other choices are also possible. Here I'll just suppose we've got some appropriate value in the variable `dummy`.
+3. When `expr1` evaluates to a `store_index` and `expr2` evaluates to an `int`, then **setref expr1 expr2** should have the effect of changing the store so that the reference cell at that index now contains that `int`. We have to make a decision about what result the `setref ...` call should itself evaluate to; OCaml makes this `()` but other choices are also possible. Here I'll just suppose we've got some appropriate value in the variable `dummy`.
- let rec eval expression g s =
- match expression with
- ...
- | Setref (expr1, expr2) ->
- let (Index n, s') = eval expr1 g s
- (* note that s' may be different from s, if expr1 itself contained any mutation operations *)
- in let (new_value, s'') = eval expr2 g s'
- (* now we create a list which is just like s'' except it has new_value in index n *)
- in let rec replace_nth lst m =
- match lst with
- | [] -> failwith "list too short"
- | x::xs when m = 0 -> new_value :: xs
- | x::xs -> x :: replace_nth xs (m - 1)
- in let s''' = replace_nth s'' n
- in (dummy, s''')
- ...
+ let rec eval expression e s =
+ match expression with
+ ...
+ | Setref (expr1, expr2) ->
+ let (Index n, s') = eval expr1 e s in
+ (* note that s' may be different from s, if expr1 itself contained any mutation operations *)
+ let (new_value, s'') = eval expr2 e s' in
+ (* now we create a list which is just like s'' except it has new_value in index n *)
+ (* the following could be expressed in Juli8 as `modify m (fun _ -> new_value) xs` *)
+ let rec replace_nth m xs = match xs with
+ | [] -> failwith "list too short"
+ | x::xs when m = 0 -> new_value :: xs
+ | x::xs -> x :: replace_nth (m - 1) xs in
+ let s''' = replace_nth n s'' in
+ (dummy, s''')
+ ...
##How to implement implicit-style mutable variables##
-With implicit-style mutation, we don't have new syntactic forms like `newref` and `deref`. Instead, we just treat ordinary variables as being mutable. You could if you wanted to have some variables be mutable and others not; perhaps the first sort are written in Greek and the second in Latin. But we will suppose all variables in our language are mutable.
+With implicit-style mutation, we don't have new syntactic forms like `newref` and `deref`. Instead, we just treat ordinary variables as being mutable. You could if you wanted to have some variables be mutable and others not; perhaps the first sort are written in Greek and the second in Latin. But for present purposes, we will suppose all variables in our language are mutable.
We will still need a store to keep track of reference cells and their current values, just as in the explicit-style implementation. This time, every variable will be associated with an index into the store. So this is what we'll have our assignment function keep track of. The assignment function will bind variables to indexes into the store, rather than to the variables' current values. The variables will only indirectly be associated with "their values" by virtue of the joint work of the assignment function and the store.
To handle implicit-style mutation, we'll need to re-implement the way we interpret expressions like `x` and `let x = expr1 in expr2`. We will also have just one new syntactic form, `change x to expr1 then expr2`.
-Here's how to implement these. We'll suppose that our assignment function is list of pairs, as above and as in [week7](/reader_monad_for_variable_binding).
-
- let rec eval expression g s =
- match expression with
- ...
- | Var (c : char) ->
- let index = List.assoc c g
- (* retrieve the value at that index in the current store *)
- in let value = List.nth s index
- in (value, s)
-
- | Let ((c : char), expr1, expr2) ->
- let (starting_val, s') = eval expr1 g s
- (* get next free index in s' *)
- in let new_index = List.length s'
- (* insert starting_val there *)
- in let s'' = List.append s' [starting_val]
- (* evaluate expr2 using a new assignment function and store *)
- in eval expr2 ((c, new_index) :: g) s''
-
- | Change ((c : char), expr1, expr2) ->
- let (new_value, s') = eval expr1 g s
- (* lookup which index is associated with Var c *)
- in let index = List.assoc c g
- (* now we create a list which is just like s' except it has new_value at index *)
- in let rec replace_nth lst m =
- match lst with
- | [] -> failwith "list too short"
- | x::xs when m = 0 -> new_value :: xs
- | x::xs -> x :: replace_nth xs (m - 1)
- in let s'' = replace_nth s' index
- (* evaluate expr2 using original assignment function and new store *)
- in eval expr2 g s''
-
-Note: Chris uses this kind of machinery on the third page of the Nov 22 handout. Except he implements `Let` the way we here implement `Change`. And he adds an implementation of `Alias` (see below). Some minor differences: on his handout (and following Groenendijk, Stokhof and Veltman), he uses `r` and `g` where we use `g` and `s` respectively. Also, he implements his `r` with a function from `char` to `int`, instead of a `(char * int) list`, as we do here. It should be obvious how to translate between these. His implementation requires that variables always already have an associated peg. So that when we call `Let(c, expr1, expr2)` for the first time with `c`, there's a peg whose value is to be updated. That's easier to ensure when you implement the assignment as a function than as a `(char * int) list`.
+Here's how to implement these. We'll suppose that our assignment function is list of pairs, as above and as in [week7](/reader_monad_for_variable_binding). LINK
+
+ let rec eval expression e s =
+ match expression with
+ ...
+ | Var (var : identifier) ->
+ let index = List.assoc var e in
+ (* retrieve the value at that index in the current store *)
+ let res = List.nth s index in
+ (res, s)
+
+ | Let ((var : identifier), expr1, expr2) ->
+ let (starting_val, s') = eval expr1 e s in
+ (* get next free index in s' *)
+ let new_index = List.length s' in
+ (* insert starting_val there *)
+ let s'' = List.append s' [starting_val] in
+ (* evaluate expr2 using a new assignment function and store *)
+ eval expr2 ((var, new_index) :: e) s''
+
+ | Change ((var : identifier), expr1, expr2) ->
+ let (new_value, s') = eval expr1 e s in
+ (* lookup which index is associated with Var var *)
+ let index = List.assoc var e in
+ (* now we create a list which is just like s' except it has new_value at index *)
+ let rec replace_nth lst m = match lst with
+ | [] -> failwith "list too short"
+ | x::xs when m = 0 -> new_value :: xs
+ | x::xs -> x :: replace_nth xs (m - 1) in
+ let s'' = replace_nth s' index in
+ (* evaluate expr2 using original assignment function and new store *)
+ eval expr2 e s''
+
+Note: Chris uses this kind of machinery on the third page of the Nov 22 handout. Except he implements `Let` the way we here implement `Change`. And he adds an implementation of `Alias` (see below). Some minor differences: on his handout (and following Groenendijk, Stokhof and Veltman), he uses `r` and `e` where we use `e` and `s` respectively. Also, he implements his `r` with a function from `identifier` to `int`, instead of a `(identifier * int) list`, as we do here. It should be obvious how to translate between these. His implementation requires that variables always already have an associated peg. So that when we call `Let(var, expr1, expr2)` for the first time with `var`, there's a peg whose value is to be updated. That's easier to ensure when you implement the assignment as a function than as a `(identifier * int) list`.
##How to implement mutation with a State monad##
-It's possible to do all of this monadically, and so using a language's existing resources, instead of adding new syntactic forms and new interpretation rules to the semantics. The patterns we use to do this in fact closely mirror the machinery described above.
+It's possible to do all of this monadically, instead of adding new syntactic forms and new interpretation rules to a language's semantics. The patterns we use to do this in fact closely mirror the machinery described above.
We call this a State monad. It's a lot like the Reader monad, except that with the Reader monad, we could only read from the environment. We did have the possibility of interpreting sub-expressions inside a "shifted" environment, but as you'll see, that corresponds to the "shadowing" behavior described before, not to the mutation behavior that we're trying to implement now.
Here's the implementation of the State monad, together with an implementation of the Reader monad for comparison:
- type env = (char * int) list;;
- (* alternatively, an env could be implemented as type char -> int *)
-
- type 'a reader = env -> 'a;;
- let reader_unit (value : 'a) : 'a reader =
- fun e -> value;;
- let reader_bind (u : 'a reader) (f : 'a -> 'b reader) : 'b reader =
- fun e -> let a = u e
- in let u' = f a
- in u' e;;
-
- type store = int;;
- (* very simple store, holds only a single int *)
- (* this corresponds to having only a single mutable variable *)
-
- type 'a state = store -> ('a, store);;
- let state_unit (value : 'a) : 'a state =
- fun s -> (value, s);;
- let state_bind (u : 'a state) (f : 'a -> 'b state) : 'b state =
- fun s -> let (a, s') = u s
- in let u' = f a
- in u' s';;
+ type env = (identifier * int) list;;
+ (* alternatively, an env could be implemented as type identifier -> int *)
+
+ type 'a reader = env -> 'a;;
+ let reader_mid (x : 'a) : 'a reader =
+ fun e -> x;;
+ let reader_mbind (xx : 'a reader) (k : 'a -> 'b reader) : 'b reader =
+ fun e -> let x = xx e in
+ let yy = k x in
+ yy e;;
+
+ type store = int;;
+ (* very simple store, holds only a single int *)
+ (* this corresponds to having only a single mutable variable *)
+
+ type 'a state = store -> ('a, store);;
+ let state_mid (x : 'a) : 'a state =
+ fun s -> (x, s);;
+ let state_mbind (xx : 'a state) (k : 'a -> 'b state) : 'b state =
+ fun s -> let (x, s') = xx s in
+ let yy = k x in
+ yy s';;
Notice the similarities (and differences) between the implementation of these two monads.
-With the Reader monad, we also had some special-purpose operations, beyond its general monadic operations. These were `lookup` and `shift`. With the State monad, we'll also have some special-purpose operations. We'll consider two basic ones here. One will be to retrieve what is the current store. This is like the Reader monad's `lookup`, except in this simple implementation there's only a single location for a value to be looked up from. Here's how we'll do it:
-
- let state_get : store state =
- fun s -> (s, s);;
-
-This passes through the current store unaltered, and also returns a copy of the store as its value. We can use this operation like this:
-
- some_existing_state_monad_box >>= fun _ -> state_get >>= (fun cur_store -> ...)
-
-The `fun _ ->` part here discards the value wrapped by `some_existing_state_monad_box`. We're only going to pass through, unaltered, whatever *store* is generated by that monadic box. We also wrap that store as *our own value*, which can be retrieved by further operations in the `... >>= ...` chain, such as `(fun cur_store -> ...)`.
+With the Reader monad, we also had some special-purpose operations, beyond its general monadic operations. Two to focus on were `asks` and `shift`. We would call `asks` with a helper function like `lookup "x"` that looked up a given variable in an environment. And we would call `shift` with a helper function like `insert "x" new_value` that operated on an existing environment to return a new one.
-The other operation for the State monad will be to update the existing store to a new one. This operation looks like this:
-
- let state_put (new_store : int) : dummy state =
- fun s -> (dummy, new_store);;
-
-If we want to stick this in a `... >>= ...` chain, we'll need to prefix it with `fun _ ->` too, like this:
-
- some_existing_state_monad_box >>= fun _ -> state_put 100 >>= ...
+With the State monad, we'll also have some special-purpose operations. We'll consider two basic ones here. One will be to retrieve what is the current store. This is like the Reader monad's `asks (lookup "x")`, except in this simple implementation there's only a single location for a value to be looked up from. Here's how we'll do it:
-In this usage, we don't care what value is wrapped by `some_existing_state_monad_box`. We don't even care what store it generates, since we're going to replace that store with our own new store. A more complex kind of `state_put` operation might insert not just some constant value as the new store, but rather the result of applying some function to the existing store. For example, we might want to increment the current store. Here's how we could do that:
+ let state_get : store state =
+ fun s -> (s, s);;
- some_existing_state_monad_box >>= fun _ -> state_get >>= (fun cur_store -> state_put (cur_store + 1) >>= ...
-
-We can of course define more complex functions that perform the `state_get >>= (fun cur_store -> state_put (cur_store + 1)` as a single operation.
-
-In general, a State monadic **box** (type `'a state`, what appears at the start of a `... >>= ... >>= ...` chain) is an operation that accepts some starting store as input---where the store might be simple as it is here, or much more complex---and returns a value plus a possibly modified store. This can be thought of as a static encoding of some computation on a store, which encoding is used as a box wrapped around a value of type `'a`. (And also it's a burrito.)
-
-State monadic **operations** (type `'a -> 'b state`, what appears anywhere in the middle or end of a `... >>= ... >>= ...` chain) are operations that generate new State monad boxes, based on what value was wrapped by the preceding elements in the `... >>= ... >>= ...` chain. The computations on a store that these encode (which their values may or may not be sensitive to) will be chained in the order given by their position in the `... >>= ... >>= ...` chain. That is, the computation encoded by the first element in the chain will accept a starting store s0 as input, and will return (a value and) a new store s1 as output, the next computation will get s1 as input and will return s2 as output, the next computation will get s2 as input, ... and so on.
-
-To get the whole process started, the complex computation so defined will need to be given a starting store. So we'd need to do something like this:
+This passes through the current store unaltered, and also returns a copy of the store as its payload. (What exactly corresponds to this is the simpler Reader operation `ask`.) We can use the `state_get` operation like this:
- let computation = some_state_monadic_box >>= operation >>= operation
- in computation initial_store;;
+ some_existing_state_monad_box >>= fun _ -> state_get >>= (fun cur_store -> ...)
+The `fun _ ->` part here discards the payload wrapped by `some_existing_state_monad_box`. We're only going to pass through, unaltered, whatever *store* is generated by that monadic box. We also wrap that store as *our own payload*, which can be retrieved by further operations in the `... >>= ...` chain, such as `(fun cur_store -> ...)`.
-* See also our [[State Monad Tutorial]].
+As we've mentione elsewhere, `xx >>= fun _ -> yy` can be abbreviated as `xx >> yy`.
+The other operation for the State monad will be to update the existing store to a new one. This operation looks like this:
-##Aliasing or Passing by reference##
+ let state_put (new_store : int) : dummy state =
+ fun s -> (dummy, new_store);;
--- FIXME --
+If we want to stick this in a `... >>= ...` chain, we'll need to prefix it with `fun _ ->` too, like this:
- [H] ; *** aliasing ***
- let y be 2 in
- let x be y in
- let w alias y in
- (y, x, w)
- ; evaluates to (2, 2, 2)
+ some_existing_state_monad_box >>= fun _ -> state_put 100 >>= ...
- [I] ; mutation plus aliasing
- let y be 2 in
- let x be y in
- let w alias y in
- change y to 3 then
- (y, x, w)
- ; evaluates to (3, 2, 3)
+Or:
- [J] ; as we already know, these are all equivalent:
-
- let f be (lambda (y) -> BODY) in ; #1
- ... f (EXPRESSION) ...
-
- (lambda (y) -> BODY) EXPRESSION ; #2
-
- let y be EXPRESSION in ; #3
- ... BODY ...
+ some_existing_state_monad_box >> state_put 100 >>= ...
- [K] ; *** passing by reference ***
- ; now think: "[J#1] is to [J#3] as [K#1] is to [K#2]"
-
- ? ; #1
-
- let w alias y in ; #2
- ... BODY ...
-
- ; We introduce a special syntactic form to supply
- ; the missing ?
-
- let f be (lambda (alias w) -> ; #1
- BODY
- ) in
- ... f (y) ...
+In this usage, we don't care what payload is wrapped by `some_existing_state_monad_box`. We don't even care what store it generates, since we're going to replace that store with our own new store. A more complex kind of `state_put` operation might insert not just some constant value as the new store, but rather the result of applying some function to the existing store. For example, we might want to increment the current store. Here's how we could do that:
- [L] let f be (lambda (alias w) ->
- change w to 2 then
- w + 2
- ) in
- let y be 1 in
- let z be f (y) in
- ; y is now 2, not 1
- (z, y)
- ; evaluates to (4, 2)
+<pre>
+some_existing_state_monad_box >> <span class=ul>state_get >>= (fun cur_store -> state_put (succ cur_store)</span> >>= ...
+</pre>
- [M] ; hyper-evaluativity
- let h be 1 in
- let p be 1 in
- let f be (lambda (alias x, alias y) ->
- ; contrast here: "let z be x + y + 1"
- change y to y + 1 then
- let z be x + y in
- change y to y - 1 then
- z
- ) in
- (f (h, p), f (h, h))
- ; evaluates to (3, 4)
+We can define more complex functions that perform the underlined part `state_get >>= (fun cur_store -> state_put (succ cur_store)` as a single operation. In the Juli8 and Haskell monad libraries, this is expressed by the State monad operation `modify succ`.
-Notice: in [M], `h` and `p` have same value (1), but `f (h, p)` and `f (h, h)` differ.
+In general, a State monadic **value** (type `'a state`, what appears at the start of a `... >>= ... >>= ...` chain) is an operation that accepts some starting store as input---where the store might be simple as it is here, or much more complex---and returns a payload plus a possibly modified store. This can be thought of as a static encoding of some computation on a store, which encoding is used as a box wrapped around a value of type `'a`. (And also it's a burrito.)
-See Pryor's "[Hyper-Evaluativity](http://www.jimpryor.net/research/papers/Hyper-Evaluativity.txt)".
+State monadic **operations** or Kleisli arrows (type `'a -> 'b state`, what appears anywhere in the middle or end of a `... >>= ... >>= ...` chain) are operations that generate new State monad boxes, based on what value was wrapped by the preceding elements in the `... >>= ... >>= ...` chain. The computations on a store that these encode (which their values may or may not be sensitive to) will be chained in the order given by their position in the `... >>= ... >>= ...` chain. That is, the computation encoded by the first element in the chain will accept a starting store s0 as input, and will return (a value and) a new store s1 as output, the next computation will get s1 as input and will return s2 as output, the next computation will get s2 as input, ... and so on.
+To get the whole process started, the complex computation so defined will need to be given a starting store. So we'd need to do something like this:
-##Four grades of mutation involvement##
+ let computation = some_state_monadic_box >>= operation >>= operation in
+ computation initial_store;;
-Programming languages tend to provide a bunch of mutation-related capabilities at once, if they provide any. For conceptual clarity, however, it's helped me to distill these into several small increments.
-* At the first stage, we have a purely functional language, like we've been working with up until this week.
+* See also our [[State Monad Tutorial]]. LINK
-* One increment would be to add aliasing or passing by reference, as illustrated above. In the illustration, we relied on the combination of passing by reference and mutation to demonstrate how you could get different behavior depending on whether an argument was passed to a function by reference or instead passed in the more familiar way (called "passing by value"). However, it would be possible to have passing by reference in a language without having mutation. For it to make any difference whether an argument is passed by reference or by value, such a language would have to have some primitive predicates which are sensitive to whether their arguments are aliased or not. In Jim's paper linked above, he calls such predicates "hyper-evaluative."
- The simplest such predicate we might call "hyperequals": `y hyperequals w` should evaluate to true when and only when the arguments `y` and `w` are aliased.
+##Some grades of mutation involvement##
-* Another increment would be to add implicit-style mutable variables, as we explained above. You could do this with or without also adding passing-by-reference.
+Programming languages tend to provide a bunch of mutation-related capabilities at once, if they provide any. For conceptual clarity, however, it's helped me to distill these into several small increments. This is a list of some different ways in which languages might involve mutation-like idioms. (It doesn't exhaust all the interesting such ways, but only the ones we've so far touched on.)
- The semantic machinery for implicit-style mutable variables will have something playing the role of a reference cell. However these won't be **first-class values** in the language. For something to be a first-class value, it has to be possible to assign that value to variables, to pass it as an argument to functions, and to return it as the result of a function call. Now for some of these criteria it's debatable that they are already here satisfied. For example, in some sense the introduction of a new implicitly mutable variable (`let x = 1 in ...`) will associate a reference cell with `x`. That won't be what `x` evaluates to, but it will be what the assignment function *binds* `x` to, behind the scenes. Similarly, if we bring in passing by reference, then again in some sense we are passing reference cells as arguments to functions. Not explicitly---in a context like:
+* At the zeroth stage, we have a purely functional language, like we've been working with up until this week.
- let f = (lambda (alias w) -> ...)
- in let x = 1
- in f (x)
- the expression `w` won't evaluate to a reference cell anywhere inside the `...`. But it will be associated with a reference cell, in the same way that `x` is (and indeed, with the same reference cell).
+* One increment would be to add implicit-style mutable variables, as we explained above. You could do this with or without also adding passing-by-reference.
- However, in language with implicit-style mutation, even when combined with passing by reference, what you're clearly not able to do is to return a reference cell as the result of a function call, or indeed of any expression. This is connected to---perhaps it's the same point as---the fact that `x` and `w` don't evalute to reference cells, but rather to the values that the reference cell they're implicitly associated with contains, at that stage in the computation.
+ The semantic machinery for implicit-style mutable variables will have something playing the role of a reference cell. However these won't be **first-class values** in the language. For something to be a first-class value, it has to be possible to assign that value to variables, to pass it as an argument to functions, and to return it as the result of a function call. Now for some of these criteria it's debatable that they are already here satisfied. For example, in some sense the introduction of a new implicitly mutable variable (`var x = 1 in ...`) will associate a reference cell with `x`. That won't be what `x` evaluates to, but it will be what the assignment function *binds* `x` to, behind the scenes.
-* A third grade of mutation involvement is to have explicit-style mutation. Here we might say we have not just mutable variables but also first-class values whose contents can be altered. That is, we have not just mutable variables but **mutable values**.
+ However, in language with implicit-style mutation, what you're clearly not able to do is to return a reference cell as the result of a function call, or indeed of any expression. This is connected to---perhaps it's the same point as---the fact that `x` doesn't evalute to a reference cell, but rather to the value that the reference cell it's implicitly associated with contains, at that stage in the computation.
- This introduces some interesting new conceptual possibilities. For example, what should be the result of the following fragment?
+* Another grade of mutation involvement is to have explicit-style mutation. Here we might say we have not just mutable variables but also first-class values whose contents can be altered. That is, we have not just mutable variables but **mutable values**.
- let ycell = ref 1
- in let xcell = ref 1
- in ycell = xcell
+ This introduces some interesting new conceptual possibilities. For example, what should be the result of the following fragment?
- Are the two reference cell values equal or aren't they? Well, at this stage in the computation, they're qualitatively indiscernible. They're both `int ref`s containing the same `int`. And that is in fact the relation that `=` expresses in OCaml. In Scheme the analogous relation is spelled `equal?` Computer scientists sometimes call this relation "structural equality."
+ let ycell = ref 1 in
+ let xcell = ref 1 in
+ ycell = xcell
- On the other hand, these are numerically *two* reference cells. If we mutate one of them, the other one doesn't change. For example:
+ Are the two reference cell values equal or aren't they? Well, at this stage in the computation, they're qualitatively indiscernible. They're both `int ref`s containing the same `int`. And that is in fact the relation that `=` expresses in OCaml. In Scheme the analogous relation is spelled `equal?` Computer scientists sometimes call this relation "structural equality."
- let ycell = ref 1
- in let xcell = ref 1
- in ycell := 2
- in !xcell;;
- (* evaluates to 1, not to 2 *)
+ On the other hand, these are numerically *two* reference cells. If we mutate one of them, the other one doesn't change. For example:
- So we have here the basis for introducing a new kind of equality predicate into our language, which tests not for qualitative indiscernibility but for numerical equality. In OCaml this relation is expressed by the double equals `==`. In Scheme it's spelled `eq?` Computer scientists sometimes call this relation "physical equality". Using this equality predicate, our comparison of `ycell` and `xcell` will be `false`, even if they then happen to contain the same `int`.
+ let ycell = ref 1 in
+ let xcell = ref 1 in
+ ycell := 2; !xcell;;
+ (* evaluates to 1, not to 2 *)
- Isn't this interesting? Intuitively, elsewhere in math, you might think that qualitative indicernibility always suffices for numerical identity. Well, perhaps this needs discussion. In some sense the imaginary numbers ι and -ι are qualitatively indiscernible, but numerically distinct. However, arguably they're not *fully* qualitatively indiscernible. They don't both bear all the same relations to ι for instance. But then, if we include numerical identity as a relation, then `ycell` and `xcell` don't both bear all the same relations to `ycell`, either. Yet there is still a useful sense in which they can be understood to be qualitatively equal---at least, at a given stage in a computation.
+ So we have here the basis for introducing a new kind of equality predicate into our language, which tests not for qualitative indiscernibility but for numerical equality. In OCaml this relation is expressed by the double equals `==`. In Scheme it's spelled `eq?` Computer scientists sometimes call this relation "physical equality". Using this equality predicate, our comparison of `ycell` and `xcell` will be `false`, even if they then happen to contain the same `int`.
- Terminological note: in OCaml, `=` and `<>` express the qualitative (in)discernibility relations, also expressed in Scheme with `equal?`. In OCaml, `==` and `!=` express the numerical (non)identity relations, also expressed in Scheme with `eq?`. `=` also has other syntactic roles in OCaml, such as in the form `let x = value in ...`. In other languages, like C and Python, `=` is commonly used just for assignment (of either of the sorts we've now seen: `let x = value in ...` or `change x to value in ...`). The symbols `==` and `!=` are commonly used to express qualitative (in)discernibility in these languages. Python expresses numerical (non)identity with `is` and `is not`. What an unattractive mess. Don't get me started on Haskell (qualitative discernibility is `/=`) and Lua (physical (non)identity is `==` and `~=`).
+ Isn't this interesting? Intuitively, elsewhere in math, you might think that qualitative indicernibility always suffices for numerical identity. Well, perhaps this needs discussion. In some sense the imaginary numbers ι and -ι are qualitatively indiscernible, but numerically distinct. However, arguably they're not *fully* qualitatively indiscernible. They don't both bear all the same relations to ι for instance. But then, if we include numerical/physical identity as a relation, then `ycell` and `xcell` don't both bear all the same relations to `ycell`, either. Yet there is still a useful sense in which they can be understood to be qualitatively equal---at least, at a given stage in a computation.
- Because of the particular way the numerical identity predicates are implemented in all of these languages, it doesn't quite match our conceptual expectations. For instance, For instance, if `ycell` is a reference cell, then `ref !ycell` will always be a numerically distinct reference cell containing the same value. We get this pattern of comparisons in OCaml:
+ Terminological note: in OCaml, `=` and `<>` express the qualitative (in)discernibility relations, also expressed in Scheme with `equal?`. In OCaml, `==` and `!=` express the numerical (non)identity relations, also expressed in Scheme with `eq?`. `=` also has other syntactic roles in OCaml, such as in the form `let x = value in ...`. In other languages, like C and Python, `=` is commonly used just for assignment (of either of the sorts we've now seen: `var x = value in ...` or `set x to value in ...`). The symbols `==` and `!=` are commonly used to express qualitative (in)discernibility in these languages. Python expresses numerical (non)identity with `is` and `is not`. What an unattractive mess. Don't get me started on Haskell (qualitative discernibility is `/=`) and Lua (physical (non)identity is `==` and `~=`).
- ycell == ycell
- ycell != ref !ycell (* true, these aren't numerically identical *)
+ Because of the particular way the numerical identity predicates are implemented in all of these languages, it doesn't quite match our conceptual expectations. For instance, For instance, if `ycell` is a reference cell, then `ref !ycell` will always be a numerically distinct reference cell containing the same value. We get this pattern of comparisons in OCaml:
- ycell = ycell
- ycell = ref !ycell (* true, they are qualitatively indiscernible *)
+ ycell == ycell
+ ycell != ref !ycell (* true, these aren't numerically identical *)
- But now what about?
+ ycell = ycell
+ ycell = ref !ycell (* true, they are qualitatively indiscernible *)
- (0, 1, ycell) ? (0, 1, ycell)
- (0, 1. ycell) ? (0, 1. ref !ycell)
+ But now what about?
- You might expect the first pair to be numerically identical too---after all, they involve the same structure (an immutable triple) each of whose components is numerically identical. But OCaml's "physical identity" predicate `==` does not detect that identity. It counts both of these comparisons as false. OCaml's `=` predicate does count the first pair as equal, but only because it's insensitive to numerical identity; it also counts the second pair as equal. This shows up in all the other languages I know, as well. In Python, `y = []; (0, 1, y) is (0, 1, y)` evaluates to false. In Racket, `(define y (box 1)) (eq? (cons 0 y) (cons 0 y))` also evaluates to false (and in Racket, unlike traditional Schemes, `cons` is creating immutable pairs). They chose an implementation for their numerical identity predicates that is especially efficient and does the right thing in the common cases, but doesn't quite match our mathematical expectations.
+ (0, 1, ycell) ? (0, 1, ycell)
+ (0, 1. ycell) ? (0, 1. ref !ycell)
- Additionally, note that none of the equality predicates so far considered is the same as the "hyperequals" predicate mentioned above. For example, in the following (fictional) language:
+ You might expect the first pair to be numerically identical too---after all, they involve the same structure (an immutable triple) each of whose components is numerically identical. But OCaml's "physical identity" predicate `==` does not detect that identity. It counts both of these comparisons as false. OCaml's `=` predicate does count the first pair as equal, but only because it's insensitive to numerical identity; it also counts the second pair as equal. This shows up in all the other languages I know, as well. In Python, `y = []; (0, 1, y) is (0, 1, y)` evaluates to false. In Racket, `(define y (box 1)) (eq? (cons 0 y) (cons 0 y))` also evaluates to false (and in Racket, unlike traditional Schemes, `cons` is creating immutable pairs). They chose an implementation for their numerical identity predicates that is especially efficient and does the right thing in the common cases, but doesn't quite match our mathematical expectations.
- let ycell = ref 1
- in let xcell = ref 1
- in let wcell alias ycell
- in let zcell = ycell
- in ...
+ In the following (fictional) language:
- at the end, `hyperequals ycell wcell` (and the converse) would be true, but no other non-reflexive hyperequality would be true. `hyperequals ycell zcell` for instance would be false. If we express numerical identity using `==`, as OCaml does, then both of these (and their converses) would be true:
+ let ycell = ref 1 in
+ let xcell = ref 1 in
+ let zcell = ycell in
+ ...
- ycell == wcell
- ycell == zcell
+ If we express numerical identity using `==`, as OCaml does, then this (and its converse) would be true:
- but these would be false:
+ ycell == zcell
- xcell == ycell
- xcell == wcell
- xcell == zcell
+ but these would be false:
- If we express qualitative indiscernibility using `=`, as OCaml does, then all of the salient comparisons would be true:
+ xcell == ycell
+ xcell == zcell
- ycell = wcell
- ycell = zcell
- xcell = ycell
- ...
+ If we express qualitative indiscernibility using `=`, as OCaml does, then all of the salient comparisons would be true:
- Another interesting example of "mutable values" that illustrate the coming apart of qualitative indiscernibility and numerical identity are the `getter`/`setter` pairs we discussed earlier. Recall:
+ ycell = zcell
+ xcell = ycell
+ xcell = zcell
- let factory (starting_val : int) =
- let free_var = ref starting_value
- in let getter () =
- !free_var
- in let setter (new_value : int) =
- free_var := new_value
- in (getter, setter)
- in let (getter, setter) = factory 1
- in let (getter', setter') = factory 1
- in ...
+ Another interesting example of "mutable values" that illustrate the coming apart of qualitative indiscernibility and numerical identity are the `getter`/`setter` pairs we discussed earlier. Recall:
- After this, `getter` and `getter'` would (at least, temporarily) be qualitatively indiscernible. They'd return the same value whenever called with the same argument (`()`). So too would `adder` and `adder'` in the following example:
+ let factory (starting_val : int) =
+ let free_var = ref starting_value in
+ let getter () = !free_var in
+ let setter (new_value : int) = free_var := new_value in
+ (getter, setter) in
+ let (getter, setter) = factory 1 in
+ let (getter', setter') = factory 1 in
+ ...
- let factory (starting_val : int) =
- let free_var = ref starting_value
- in let adder x =
- x + !free_var
- in let setter (new_value : int) =
- free_var := new_value
- in (adder, setter)
- in let (adder, setter) = factory 1
- in let (adder', setter') = factory 1
- in ...
+ After this, `getter` and `getter'` would (at least, temporarily) be qualitatively indiscernible. They'd return the same value whenever called with the same argument (`()`). So too would `adder` and `adder'` in the following example:
- Of course, in most languages you wouldn't be able to evaluate a comparison like `getter = getter'`, because in general the question whether two functions always return the same values for the same arguments is not decidable. So typically languages don't even try to answer that question. However, it would still be true that `getter` and `getter'` (and `adder` and `adder'`) were extensionally equivalent; you just wouldn't be able to establish so.
+ let factory (starting_val : int) =
+ let free_var = ref starting_value in
+ let adder x = x + !free_var in
+ let setter (new_value : int) = free_var := new_value in
+ (adder, setter) in
+ let (adder, setter) = factory 1 in
+ let (adder', setter') = factory 1 in
+ ...
- However, they're not numerically identical, because by calling `setter 2` (but not calling `setter' 2`) we can mutate the function value `getter` (and `adder`) so that it's *no longer* qualitatively indiscernible from `getter'` (or `adder'`).
+ Of course, in most languages you wouldn't be able to evaluate a comparison like `getter = getter'`, because in general the question whether two functions always return the same values for the same arguments is not decidable. So typically languages don't even try to answer that question. However, it would still be true that `getter` and `getter'` (and `adder` and `adder'`) were extensionally equivalent; you just wouldn't be able to establish so.
+ However, they're not numerically identical, because by calling `setter 2` (but not calling `setter' 2`) we can mutate the function value `getter` (and `adder`) so that it's *no longer* qualitatively indiscernible from `getter'` (or `adder'`).
-
-* A fourth grade of mutation involvement: (--- FIXME ---)
+There are several more layers and complexity to the way different languages engage with mutation. But this exhausts what we're in a position to consider now.
- structured references
- (a) if `a` and `b` are mutable variables that uncoordinatedly refer to numerically the same value
- then mutating `b` won't affect `a` or its value
- (b) if however their value has a mutable field `f`, then mutating `b.f` does
- affect their shared value; will see a difference in what `a.f` now evaluates to
- (c) examples: Scheme mutable pairs, OCaml mutable arrays or records
+##Miscellany##
+* When using mutable variables, programmers will often write using *imperatival loops* that repeatedly mutate a variable, rather than the recursive techniques we've been using so far. For example, we'd define the factorial function like this:
-##Miscellany##
+ let rec factorial n =
+ if n = 0 then 1 else n * factorial (n - 1)
-* When using mutable variables, programmers will sometimes write using *loops* that repeatedly mutate a variable, rather than the recursive techniques we've been using so far. For example, we'd define the factorial function like this:
+ or like this:
- let rec factorial n =
- if n = 0 then 1 else n * factorial (n - 1)
+ let factorial n =
+ let rec aux n sofar =
+ if n = 0 then sofar else aux (n - 1) (n * sofar) in
+ aux n 1
- or like this:
+ (The second version is more efficient than the first; so you may sometimes see this programming style. But for our purposes, these can be regarded as equivalent.)
- let factorial n =
- let rec helper n sofar =
- if n = 0 then sofar else helper (n - 1) (n * sofar)
- in helper n 1
+ When using mutable variables, on the other hand, this may be written as:
- (The second version is more efficient than the first; so you may sometimes see this programming style. But for our purposes, these can be regarded as equivalent.)
+ let factorial n =
+ let current = ref n in
+ let total = ref 1 in
+ while !current > 0 do
+ total := !total * !current; current := !current - 1
+ done; !total
- When using mutable variables, on the other hand, this may be written as:
+ This is often referred to as an *iterative* as opposed to a *recursive* algorithm.
- let factorial n =
- let current = ref n
- in let total = ref 1
- in while !current > 0 do
- total := !total * !current; current := !current - 1
- done; !total
+* Mutable variables also give us a way to achieve recursion, in a language that doesn't already have it. For example:
-* Mutable variables also give us a way to achieve recursion, in a language that doesn't already have it. For example:
+ let fact_cell = ref None in
+ let factorial n =
+ if n = 0 then 1 else match !fact_cell with
+ | Some fact -> n * fact (n - 1)
+ | None -> failwith "can't happen" in
+ let () = fact_cell := Some factorial in
+ ...
- let fact_cell = ref None
- in let factorial n =
- if n = 0 then 1 else match !fact_cell with
- | Some fact -> n * fact (n - 1)
- | None -> failwith "can't happen"
- in let () = fact_cell := Some factorial
- in ...
+ We use the `None`/`Some factorial` option type here just as a way to ensure that the contents of `fact_cell` are of the same type both at the start and the end of the block.
- We use the `None`/`Some factorial` option type here just as a way to ensure that the contents of `fact_cell` are of the same type both at the start and the end of the block.
+ If you've got a copy of *The Seasoned Schemer*, which we recommended for the seminar, see the discussion at pp. 118-125.
- If you've got a copy of *The Seasoned Schemer*, which we recommended for the seminar, see the discussion at pp. 118-125.
+<!--
+* Now would be a good time to go back and review some material from [[week1]], and seeing how much we've learned. There's discussion back then of declarative or functional languages versus languages using imperatival features, like mutation. Mutation is distinguished from shadowing. There's discussion of sequencing, and of what we mean by saying "order matters."
-* Now would be a good time to go back and review some material from [[week1]], and seeing how much we've learned. There's discussion back then of declarative or functional languages versus languages using imperatival features, like mutation. Mutation is distinguished from shadowing. There's discussion of sequencing, and of what we mean by saying "order matters."
+ In point 7 of the Rosetta Stone discussion, the contrast between call-by-name and call-by-value evaluation order appears (though we don't yet call it that). We'll be discussing that more in coming weeks. In the [[damn]] example, continuations and other kinds of side effects (namely, printing) make an appearance. These too will be center-stage in coming weeks.
- In point 7 of the Rosetta Stone discussion, the contrast between call-by-name and call-by-value evaluation order appears (though we don't yet call it that). We'll be discussing that more in coming weeks. In the [[damn]] example, continuations and other kinds of side-effects (namely, printing) make an appearance. These too will be center-stage in coming weeks.
-
-* Now would also be a good time to read [Calculator Improvements](/week10). This reviews the different systems discussed above, as well as other capabilities we can add to the calculators introduced in [week7](/reader_monad_for_variable_binding). We will be building off of that in coming weeks.
+* Now would also be a good time to read [Calculator Improvements](/week10). This reviews the different systems discussed above, as well as other capabilities we can add to the calculators introduced in [week7](/reader_monad_for_variable_binding). We will be building off of that in coming weeks.
+-->
##Offsite Reading##
-* [[!wikipedia Declarative programming]]
-* [[!wikipedia Functional programming]]
-* [[!wikipedia Purely functional]]
-* [[!wikipedia Side effect (computer science) desc="Side effects"]]
-* [[!wikipedia Referential transparency (computer science)]]
-* [[!wikipedia Imperative programming]]
-* [[!wikipedia Reference (computer science) desc="References"]]
-* [[!wikipedia Pointer (computing) desc="Pointers"]]
-* [Pointers in OCaml](http://caml.inria.fr/resources/doc/guides/pointers.html)
+* [[!wikipedia Declarative programming]]
+* [[!wikipedia Functional programming]]
+* [[!wikipedia Purely functional]]
+* [[!wikipedia Side effect (computer science) desc="Side effects"]]
+* [[!wikipedia Referential transparency (computer science)]]
+* [[!wikipedia Imperative programming]]
+* [[!wikipedia Reference (computer science) desc="References"]]
+* [[!wikipedia Pointer (computing) desc="Pointers"]]
+* [Pointers in OCaml](http://caml.inria.fr/resources/doc/guides/pointers.html)
<!--
# General issues about variables and scope in programming languages #
-* [[!wikipedia Variable (programming) desc="Variables"]]
-* [[!wikipedia Free variables and bound variables]]
-* [[!wikipedia Variable shadowing]]
-* [[!wikipedia Name binding]]
-* [[!wikipedia Name resolution]]
-* [[!wikipedia Parameter (computer science) desc="Function parameters"]]
-* [[!wikipedia Scope (programming) desc="Variable scope"]]
-* [[!wikipedia Closure (computer science) desc="Closures"]]
+* [[!wikipedia Variable (programming) desc="Variables"]]
+* [[!wikipedia Free variables and bound variables]]
+* [[!wikipedia Variable shadowing]]
+* [[!wikipedia Name binding]]
+* [[!wikipedia Name resolution]]
+* [[!wikipedia Parameter (computer science) desc="Function parameters"]]
+* [[!wikipedia Scope (programming) desc="Variable scope"]]
+* [[!wikipedia Closure (computer science) desc="Closures"]]
-->
+
+