+ *Comments*:
+
+ 1. The technique deployed here, and in the v2 lists, and in our implementations
+ of pairs and booleans, is known as **continuation-passing style** programming.
+
+ 2. We're still building the list as a right fold, so in a sense the
+ application of `f` to the leftmost element `5` is "outermost". However,
+ this "outermost" application is getting lifted, and passed as a *handler*
+ to the next right application. Which is in turn getting lifted, and
+ passed to its next right application, and so on. So if you
+ trace the evaluation of the `extract_head` function to the list `[5;4;3;2;1]`,
+ you'll see `1` gets passed as a "this is the head sofar" answer to its
+ `continue_handler`; then that answer is discarded and `2` is
+ passed as a "this is the head sofar" answer to *its* `continue_handler`,
+ and so on. All those steps have to be evaluated to finally get the result
+ that `5` is the outer/leftmost head of the list. That's not an efficient way
+ to get the leftmost head.
+
+ We could improve this by building lists as left folds when implementing them
+ as continuation-passing style folds. We'd just replace above:
+
+ let make_list = \h t. \f z continue_handler abort_handler.
+ f h z (\z. t f z continue_handler abort_handler) abort_handler
+
+ now `extract_head` should return the leftmost head directly, using its `abort_handler`:
+
+ let extract_head = \lst larger_computation. lst
+ (\hd sofar continue_handler abort_handler. abort_handler hd)
+ junk
+ larger_computation
+ larger_computation
+
+ 3. To extract tails efficiently, too, it'd be nice to fuse the apparatus developed
+ in these v5 lists with the ideas from the v4 lists, above.
+ But that also is left as an exercise.
+
+
+5. **Implementing (self-balancing) trees**
+
+ In [[Assignment3]] we proposed a very ad-hoc-ish implementation of trees.
+
+ Think about how you'd implement them in a more principled way. You could
+ use any of the version 1 -- version 5 implementation of lists as a model.
+
+ To keep things simple, I recommend starting with the version 3 pattern. And
+ stick to binary trees.
+
+ There are two kinds of trees to think about. In one sort of tree, it's only
+ the tree's *leaves* that are labeled:
+
+ +
+ / \
+ + 3
+ / \
+ 1 2
+
+ Linguists often use trees of this sort. The inner, non-leaf nodes of the
+tree have associated values. But what values they are can be determined from
+the structure of the tree and the values of the node's left and right children.
+So the inner node doesn't need its own independent label.
+
+ In another sort of tree, the tree's inner nodes are also labeled:
+
+ 4
+ / \
+ 2 5
+ / \
+ 1 3
+
+ When you want to efficiently arrange an ordered collection, so that it's
+ easy to do a binary search through it, this is the way you usually structure
+ your data.
+
+ These latter sorts of trees can helpfully be thought of as ones where
+ *only* the inner nodes are labeled. Leaves can be thought of as special,
+ dead-end branches with no label:
+
+ .4.
+ / \
+ 2 5
+ / \ / \
+ 1 3 x x
+ / \ / \
+ x x x x
+
+ In our earlier discussion of lists, we said they could be thought of as
+ data structures of the form:
+
+ Empty_list | Non_empty_list (its_head, its_tail)
+
+ And that could in turn be implemented in v2 form as:
+
+ the_list (\head tail. non_empty_handler) empty_handler
+
+ Similarly, the leaf-labeled tree:
+
+ +
+ / \
+ + 3
+ / \
+ 1 2
+
+ can be thought of as a data structure of the form:
+
+ Node (its_left_subtree, its_right_subtree) | Leaf (its_label)
+
+ and that could be implemented in v2 form as:
+
+ the_tree (\left right. node_handler) (\label. lead_handler)
+
+ And the node-labeled tree:
+
+ .4.
+ / \
+ 2 5
+ / \ / \
+ 1 3 x x
+ / \ / \
+ x x x x
+
+ can be thought of as a data structure of the form:
+
+ Node (its_left_subtree, its_label, its_right_subtree) | Leaf
+
+ and that could be implemented in v2 form as:
+
+ the_tree (\left label right. node_handler) leaf_result
+
+
+ What would correspond to "folding" a function `f` and base value `z` over a
+ tree? Well, if it's an empty tree:
+
+ x
+
+ we should presumably get back `z`. And if it's a simple, non-empty tree:
+
+ 1
+ / \
+ x x
+
+ we should expect something like `f z 1 z`, or `f <result of folding f and z
+ over left subtree> label_of_this_node <result of folding f and z over right
+ subtree>`. (It's not important what order we say `f` has to take its arguments
+ in.)
+
+ A v3-style implementation of node-labeled trees, then, might be:
+
+ let empty_tree = \f z. z in
+ let make_tree = \left label right. \f z. f (left f z) label (right f z) in
+ ...
+
+ Think about how you might implement other tree operations, such as getting
+the label of the root (topmost node) of a tree; extracting the left subtree of
+a node; and so on.
+
+ Think about different ways you might implement v3-style trees.
+
+ If you had one tree and wanted to make a larger tree out of it, adding in a
+new element, how would you do that?
+
+ When using trees to represent linguistic structures, one doesn't have
+latitude about *how* to build a larger tree. The linguistic structure you're
+trying to represent will determine where the new element should be placed, and
+where the previous tree should be placed.
+
+ However, when using trees as a computational tool, one usually does have
+latitude about how to structure a larger tree---in the same way that we had the
+freedom to implement our sets with lists whose members were just appended in
+the order we built the set up, or instead with lists whose members were ordered
+numerically.
+
+ When building a new tree, one strategy for where to put the new element and
+where to put the existing tree would be to always lean towards a certain side.
+For instance, to add the element `2` to the tree:
+
+ 1
+ / \
+ x x
+
+ we might construct the following tree:
+
+ 1
+ / \
+ x 2
+ / \
+ x x
+
+ or perhaps we'd do it like this instead:
+
+ 2
+ / \
+ x 1
+ / \
+ x x
+
+ However, if we always leaned to the right side in this way, then the tree
+would get deeper and deeper on that side, but never on the left:
+
+ 1
+ / \
+ x 2
+ / \
+ x 3
+ / \
+ x 4
+ / \
+ x 5
+ / \
+ x x
+
+ and that wouldn't be so useful if you were using the tree as an arrangement
+to enable *binary searches* over the elements it holds. For that, you'd prefer
+the tree to be relatively "balanced", like this:
+
+ .4.
+ / \
+ 2 5
+ / \ / \
+ 1 3 x x
+ / \ / \
+ x x x x
+
+ Do you have any ideas about how you might efficiently keep the new trees
+you're building pretty "balanced" in this way?
+
+ This is a large topic in computer science. There's no need for you to learn
+any of the various strategies that they've developed for doing this. But
+thinking in broad brush-strokes about what strategies might be promising will
+help strengthen your understanding of trees, and useful ways to implement them
+in a purely functional setting like the lambda calculus.
+