#What is computation?# The folk notion of computation involves taking a complicated expression and replacing it with an equivalent simpler expression. 3 + 4 == 7 This equation can be interpreted as expressing the thought that the complex expression `3 + 4` evaluates to `7`. In this case, the evaluation of the expression involves computing a sum. There is a clear sense in which the expression `7` is simpler than the expression `3 + 4`: `7` is syntactically simple, and `3 + 4` is syntactically complex. It's worth pausing a moment and wondering why we feel that replacing a complex expression like `3 + 4` with a simplex expression like `7` feels like we've accomplished something. If they really are equivalent, why shouldn't we consider them to be equally valuable, or even to prefer the longer expression? For instance, should we prefer 2^9, or 512? Likewise, in the realm of logic, why shold we ever prefer `B` to the conjunction of `A` with `A --> B`? The question to ask here is whether our intuitions about what counts as more evaluated always tracks simplicity of expression, or whether it tracks what is more useful to us in a given larger situation. But even deciding which expression ought to count as simpler is not always so clear. ##Church arithmetic## In our system of computing with Church encodings, we have the following representations: 3 := \f z . f (f (f z)) 4 := \f z . f (f (f (f z))) 7 := \f z . f (f (f (f (f (f (f z)))))) [By the way, those of you who did the extra credit problem on homework 2, solving the reverse function with Oleg's holes---do you see the resemblance?] The addition of 3 and 4, then, clearly needs to just tack 4's string of f's onto the end of 3's string of f's. This suggests the following implementation of the arithmetic addition: + := \lrfz.lf(rfz) + 3 4 == (\lrfz.lf(rfz)) 3 4 ~~> \fz.3f(4fz) == \fz.(\fz.f(f(fz))) f (4fz) ~~> \fz.f(f(f(4fz))) == \fz.f(f(f((\fz.f(f(f(fz))) f z)))) ~~> \fz.f(f(f(f(f(f(fz)))))) == 7 as desired. Is there still a sense in which the encoded version of `3 + 4` is simpler than the encoded version of `7`? Well, yes: once the numerals `3` and `4` have been replaced with their encodings, the encoding of `3 + 4` contains more symbols than the encoding of `7`. But now consider multiplication: * := \lrf.l(rf) * 3 4 := (\lrf.l(rf)) 3 4 ~~> (\rf.3(rf)) 4 ~~> \f.3(4f) == \f.(\fz.f(f(fz)))(4f) ~~> \fz.(4f)((4f)((4f)z)) == \fz.((\fz.f(f(f(fz))))f) (((\fz.f(f(f(fz))))f) (((\fz.f(f(f(fz))))f) z)) ~~> \fz.((\z.f(f(f(fz)))) ((\z.f(f(f(fz)))) ((\z.f(f(f(fz))))z))) ~~> \fz.((\z.f(f(f(fz)))) ((\z.f(f(f(fz)))) (f(f(f(fz)))))) ~~> \fz.((\z.f(f(f(fz)))) (f(f(f(f(f(f(f(fz))))))))) ~~> \fz.f(f(f(f(f(f(f(f(f(f(f(fz))))))))))) == 12 Is the final result simpler? This time, the answer is not so straightfoward. Compare the starting expression with the final expression: * 3 4 (\lrf.l(rf))(\fz.f(f(fz)))(\fz.f(f(f(fz)))) ~~> 12 (\fz.f(f(f(f(f(f(f(f(f(f(f(fz)))))))))))) And if we choose different numbers, the result is even less clear: * 3 6 (\lrf.l(rf))(\fz.f(f(fz)))(\fz.f(f(f(f(f(fz)))))) ~~> 18 (\fz.f(f(f(f(f(f(f(f(f(f(f(f(f(f(f(f(f(fz)))))))))))))))))) On the on hand, there are more symbols in the encoding of `18` than in the encoding of `* 3 6`. On the other hand, there is more complexity (speaking pre-theoretically) in the encoding of `* 3 6`, since the encoding of `18` is just a uniform sequence of nested `f`'s. This example shows that computation can't be just simplicity as measured by the number of symbols in the representation. There is still some sense in which the evaluated expression is simpler, but the right way to characterize "simpler" is elusive. One possibility is to define simpler in terms of irreversability. The reduction rules of the lambda calculus define an asymmetric relation over terms: for any given redex, there is a unique reduced term (up to alphabetic variance). But for any given term, there are many redexes that reduce to that term. ((\x.xx)y) ~~> yy ((\xx)yy) ~~> yy (y((\xx)y)) ~~> yy etc. Likewise, in the arithmetic example, there is only one number that corresponds to the sum of 3 and 4 (namely, 7). But there are many sums that add up to 7: 3+4, 4+3, 5+2, 2+5, 6+1, 1+6, etc. So the unevaluated expression contains information that is missing from the evaluated value: information about *how* that value was arrived at. So this suggests the following way of thinking about what counts as evaluated: Given two expressions such that one reduces to the other, the more evaluated one is the one that contains less information. This definition is problematic, though, if we try to define the amount of information using, say, [[!wikipedia Komolgorov complexity]]. Ultimately, we have to decide that the reduction rules determine what counts as evaluated. If we're lucky, that will align well with our intuitive desires about what should count as simpler. But we're not always lucky. In particular, although beta reduction in general lines up well with our intuitive sense of simplification, there are pathological examples where the results do not align so well: (\x.xx)(\x.xx) ~~> (\x.xx)(\x.xx) ~~> (\x.xx)(\x.xx) In this example, reduction returns the exact same lambda term. There is no simplification at all. (\x.xxx)(\x.xxx) ~~> ((\x.xxxx)(\x.xxxx)(\x.xxxx)) Even worse, in this case, the "reduced" form is longer and more complex by any measure. We may have to settle for the idea that a well-chosen reduction system will characterize our intuitive notion of evaluation in most cases, or in some useful class of non-pathological cases. These are some of the deeper issues to keep in mind as we discuss the ins and outs of reduction strategies.